[英]PHP Group Array values then sum
How can i group by adult price then get the sum of adult count.我如何按成人价格分组然后获得成人人数的总和。 here is my array bellow:
这是我的阵列波纹管:
Array
(
[0] => Array
(
[Reservation] => Array
(
[adult_price] => 2000
[adult_count] => 2
)
)
[1] => Array
(
[Reservation] => Array
(
[adult_price] => 2000
[adult_count] => 1
)
)
[2] => Array
(
[Reservation] => Array
(
[adult_price] => 300
[adult_count] => 1
)
)
)
Expected Result if adult_price is same thats the time that the adult_count will add:如果 Adult_price 与 Adult_count 相加的时间相同,则预期结果:
Array
(
[0] => Array
(
[Reservation] => Array
(
[adult_price] => 2000
[adult_count] => 4
)
)
[1] => Array
(
[Reservation] => Array
(
[adult_price] => 300
[adult_count] => 1
)
)
)
Please help me thank you!请帮帮我谢谢!
try something like this:尝试这样的事情:
function summarize($ReservationArr){
$summed = [];
foreach ($ReservationArr as $one){
$adult_price = $one["Reservation"]["adult_price"];
$adult_count= $one["Reservation"]["adult_count"];
if (isset( $summed[$adult_price])){
$summed[$adult_price] += (int)$adult_count;
} else {
$summed[$adult_price] = (int)$adult_count;
}
}
// now rebuild:
$result = [];
foreach ($summed as $price => $number){
$result[] = array("Reservation" => array("adult_price" => $price, "adult_count" => $number));
}
return $result;
}
$test = [];
$test[] = array("Reservation" => array("adult_price" => 2000, "adult_count" => 2));
$test[] = array("Reservation" => array("adult_price" => 1000, "adult_count" => 1));
$test[] = array("Reservation" => array("adult_price" => 500, "adult_count" => 4));
$test[] = array("Reservation" => array("adult_price" => 2000, "adult_count" => 3));
$test[] = array("Reservation" => array("adult_price" => 2000, "adult_count" => 2));
$test[] = array("Reservation" => array("adult_price" => 1000, "adult_count" => 1));
$test[] = array("Reservation" => array("adult_price" => 500, "adult_count" => 4));
$test[] = array("Reservation" => array("adult_price" => 2000, "adult_count" => 3));
$res = summarize($test);
echo "<pre>";
print_r($res);
echo "</pre>";
Try this:尝试这个:
$grouped = [];
foreach ($array as $item) {
$item = $item["Reservation"];
$currentValue = isset($grouped[$item["adult_price"]]) ? $grouped[$item["adult_price"]] : 0;
$grouped[$item["adult_price"]] = $currentValue + $item["adult_count"];
}
$buildArray = [];
foreach ($grouped as $price => $count) {
$buildArray[] = ["Reservation" => ["adult_price" => $price, "adult_count" => $count]];
}
print_r($buildArray);
Using two loops is too much unnecessary work.使用两个循环是太多不必要的工作。 Treat the output array as a continuously updated lookup array.
将输出数组视为不断更新的查找数组。 This will determine if you are dealing with a new adult_price or one that has been encountered before.
这将决定您是在处理一个新的 Adult_price 还是之前遇到过的一个。 Use the
$row['Reservation']['adult_price']
value as new temporary first level keys -- this assists isset()
in knowing if the whole row should be saved, or if the adult_count should be added to the stored count.使用
$row['Reservation']['adult_price']
值作为新的临时第一级键——这有助于isset()
知道是否应该保存整行,或者是否应该将 Adult_count 添加到存储的计数中。
$rows = [
["Reservation" => ["adult_price" => 2000, "adult_count" => 2]],
["Reservation" => ["adult_price" => 1000, "adult_count" => 1]],
["Reservation" => ["adult_price" => 500, "adult_count" => 4]],
["Reservation" => ["adult_price" => 2000, "adult_count" => 3]],
["Reservation" => ["adult_price" => 2000, "adult_count" => 2]],
["Reservation" => ["adult_price" => 1000, "adult_count" => 1]],
["Reservation" => ["adult_price" => 500, "adult_count" => 4]],
["Reservation" => ["adult_price" => 2000, "adult_count" => 3]],
];
$result = [];
foreach ($rows as $row) {
if (!isset($result[$row['Reservation']['adult_price']])) {
$result[$row['Reservation']['adult_price']] = $row;
} else {
$result[$row['Reservation']['adult_price']]['Reservation']['adult_count'] += $row['Reservation']['adult_count'];
}
}
var_export(array_values($result));
Alternatively, this may cause less eye-strain:或者,这可能会减少眼睛疲劳:
foreach ($rows as $row) {
$key = $row['Reservation']['adult_price'];
if (!isset($result[$key])) {
$result[$key] = $row;
} else {
$result[$key]['Reservation']['adult_count'] += $row['Reservation']['adult_count'];
}
}
Output: (from either snippet)输出:(来自任一片段)
array (
0 =>
array (
'Reservation' =>
array (
'adult_price' => 2000,
'adult_count' => 10,
),
),
1 =>
array (
'Reservation' =>
array (
'adult_price' => 1000,
'adult_count' => 2,
),
),
2 =>
array (
'Reservation' =>
array (
'adult_price' => 500,
'adult_count' => 8,
),
),
)
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