我们可以在Jenkins参数化构建中定义变量吗

Question

My scenario is, I have parameterized build and inside the build section, I have executed shell where I define a variable and then echo to print it. But it doesn't print anything in the console output.

I hope I have made myself clear. Could anyone please answer my question?

current_folder=`date +%Y%m%d-%H%M%S`
echo $current_folder

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Answer 1

I'm using Jenkins ver. 2.32.3 and a simple freestyle job, running on mac OS, using an execute shell build step of:

current_folder=`date +%Y%m%d-%H%M%S`
echo $current_folder

Gives output of:

$ /bin/sh -xe /var/folders/kh/4fl0eeldofefmmsfd/T/hudson89388543547899686.sh
++ date +%Y%m%d-%H%M%S
+ current_folder=20180613-081712
+ echo 20180613-081712
20180613-081712
Finished: SUCCESS

In a similar fashion, setting the shell:

#!/bin/bash
current_folder=`date +%Y%m%d-%H%M%S`
echo $current_folder

Gives:

$ /bin/bash /var/folders/kh/by0kd93dfew5fgjhy000h6/T/hudson62702345565786787.sh
20180613-081655
Finished: SUCCESS

The same applies to a parameter that is defined as part of the Jenkins job, underneath the
This project is parameterized checkbox once set. For example, if you have a string parameter called userName with a default value of User1 , then you can print it's value in an Execute Shell build step using:

echo $userName
echo ${userName}
echo "In a string ${userName}"

Giving:

User1
User1
In a string User1