正则表达式Javascript，用于匹配第一个特定字符之前的字母数字字符串中的5个非连续数字

Question

I am trying to create a regular expression in javascript that matches the last 5 non-consecutive numbers in an alphanumeric string before the first "-" like so...

Take these two strings for example:

7356CH18PRZ2506-01
45D18A234-02-01

For each example above, the match would be:

82506
18234

We are using the last 5 numbers to create a unique identifier in our application per the clients request and they have to be numbers.

I have only been able to extract consecutive numbers and since there are not 5 consecutive numbers before the first "-" in each example, all my attempts have been unsuccessful.

I should probably also mention that I am not the greatest with regular expressions. I dabble.

If anyone can point me in the right direction, I would appreciate it.

Also, I would be happy to elaborate on my issue if needed.

Answer 1

You may use this approach of match + replace

 let arr = ['7356CH18PRZ2506-01', '45D18A234-02-01', '012-45D18A234-02-01', 'foobar']; let re = /^[^-]*((?:\\d[^\\d-]*){5})-/; for (i=0; i<arr.length; i++) { let m = arr[i].match(re); if (m) { console.log(arr[i], "=>", m[1].replace(/\\D+/g, '')); } } 

Here:

• Within match we use regex /^[^-]*((?:\\d[^\\d-]*){5})-/ to match first 5 digits that may have 0 or more non-digits between them followed by very first hyphen in input
• With replace we just remove all non-digits with empty string.