比较两个数组值（如果包含）并求和

Question

How to compare two array values and get the difference.

const list1 = ['1xx', '2bbb', '3ggg', '4eee'];
const list2 = ['1xx33', '2333', '3gfffgg', '4eeeooo'];

I'd like to check if list2 values contains list1s

so 1xx33 contains 1xx and 4eeeooo contains 4eee then the result I respect to see is ['2bbb', '3ggg'] ;

const output = list1.filter( function(n) { return !this.has(n) }, new Set(list2) );

Above snippet only gives matches but not contains

Answer 1

For every entry in the first list, you must verify if there is no matching substring in any of the values in the second list.

const output = list1.filter(s => list2.every(b => (b.indexOf(s)===-1)));

This snippet creates a new list by filtering the first list, removing every entry that has at least one matching substring when compared to the other list.

If you're not familiar with arrow functions ( => ), here's the alternative:

const output = list1.filter(function(s) { return list2.every(function(b) { return (b.indexOf(s)===-1) })});