ORACLE，我如何在同一张表中使用两个不同的过滤器？

Question

I have this problem: in the same table i need to get the ID´s with have only two CODES at the same time, EX:

TABLE1

ID | CODE
1  | A
1  | B
2  | C
2  | B
3  | C
3  | A
4  | A
5  | C

Example: i need to get only the ID´s with the CODE 'A' and 'B' at same time, in the TABLE1 the answer is only the ID 1

so i count whats ID have two CODE´s:

SELECT ID
FROM TABLE1
GROUP BY ID
HAVING COUNT(CODE) = 2

And i filter whats CODE´s are 'A' OR 'B'

SELECT ID
FROM TABLE1
WHERE (CODE = 'A' OR 'B')

But how i combine this two queries?

Answer 1

A slight variation on the answer given by @Lukasz:

SELECT ID
FROM TABLE1
WHERE Code IN ('A', 'B')
GROUP BY ID
HAVING COUNT(DISTINCT Code) = 2;

Answer 2

Your question is a little ambiguous. If you want A/B together -- and other codes are allowed as well -- then:

SELECT ID
FROM TABLE1
WHERE CODE IN ('A', 'B')
GROUP BY ID
HAVING MIN(CODE) = 'A' and MAX(CODE) = 'B';

You can also use:

HAVING COUNT(DISTINCT CODE) = 2;

However, COUNT(DISTINCT) typically has worse performance.

Answer 3

You could use conditional aggregation:

SELECT ID
FROM TABLE1
GROUP BY ID 
HAVING COUNT(DISTINCT CASE WHEN Code IN('A','B') THEN Code END) = 2;

DBFiddle Demo

Answer 4

You can do :

select t1.*
from table1 t1
where not exists (select 1 from table1 t2 where t2.id = t1.id and t2.code = 'C');