使用python将列表元素转换为连续的元组

Question

a = [0, 18, 27, 43, 52, 65]

is the list of indices from which I want to access bigger list slicing with 是我要从中访问更大列表切片的索引列表

[0:18],[18:27],[27:43],[43:52], [52:65], [65:]

How to do it? 怎么做？

I have tried but i not get correct format 我已经尝试过，但是格式不正确

slicing = [index for index in (a[:-1])]

but that gives me [0, 18, 27, 43, 52] . 但这给了我[0, 18, 27, 43, 52] 。

Answer 1

Use zip : 使用zip ：

a = [0, 18, 27, 43, 52, 65]    
res = [bigger_list[x:y] for x, y in zip(a[:-1], a[1:])]

and finally, extend it: 最后，扩展它：

res.extend(bigger_list[a[-1]:])

Or to do it in a single line: 或单行执行：

res = [bigger_list[x:y] for x, y in zip(a[:-1], a[1:])] + bigger_list[a[-1]:]

Answer 2

After some tweaking and searching I found answer: 经过一些调整和搜索后，我找到了答案：

res = [bigger_list[i: a[ind+1]] for ind,i in enumerate(a[:-1])]

that also gives me slicing of bigger_list . 这也给了我slicing of bigger_list 。