简体   繁体   English

更新数据库中的多个记录,Rails中的每个记录更新一次

[英]Update multiple records in the DB, one time per record in Rails

I have a code that is updating user records in a DB, but is updating the record of each user, the number of times there are users in the database, example, I have 3 users => medic1, medic2, medic4 in the SQL you can see that it is updating them 3 times when it should be 1 time per user. 我有一个代码正在更新数据库中的用户记录,但正在更新每个用户的记录,即数据库中有用户的次数,例如,我在SQL中有3个用户=> medic1,medic2,medic4可以看到它正在对它们进行3次更新,而每个用户应该更新1次。

What my code should do is extract the users with the nested attribute period_end_date from the DB and save them in a hash, which will query the Openpay API about the status of the subscription; 我的代码应该做的是从数据库中提取具有嵌套属性period_end_date的用户,并将其保存在哈希中,该哈希将查询Openpay API的订阅状态; in the response hash I receive the data of each user and depending on the 'status' I update the values in the database with the results of the response_hash, this should be per user. 在响应哈希中,我接收每个用户的数据,并根据“状态”,使用response_hash的结果更新数据库中的值,该值应针对每个用户。 I can not see what I'm doing wrong, can you help me achieve it? 我看不到我在做什么错,您能帮我解决吗?

Here is the code, rake premium_users:get_users (lib/tasks/premium_users.rake): 以下是代码rake premium_users:get_users(lib / tasks / premium_users.rake):

namespace :premium_users do
  desc 'Get the user id & data in a hash'
  task get_users: :environment do 
    users = Medic.includes(:payment_methods).where.not payment_methods: { period_end_date: nil }
    request_hash = {}

    # Get users in a hash 
    users.each do |user|
      period_end_date = user.payment_methods.last.period_end_date

      if Date.today - period_end_date <= 172_800
        openpay_customer_id = user.payment_methods.last.openpay_customer_id
        openpay_subscription_id = user.payment_methods.last.openpay_subscription_id
        medic_id = user.payment_methods.last.medic_id
        user_hash = {}
        user_hash[medic_id] = [openpay_customer_id, openpay_subscription_id]
      else
        user_hash = {}
      end

      request_hash.merge!(user_hash) # If no users is empty => {}

      if request_hash.empty?
        puts 'No User to check!'
      else
        # Request for subscription status to Openpay
        request_hash.each_value do |value|
          openpay_customer_id = value[0]
          openpay_subscription_id = value[1]

          # Openpay API connection
          @openpay = OpenpayApi.new(ENV['MERCHANT_ID_OPENPAY'], ENV['SECRET_KEY_OPENPAY'])
          @subscriptions = @openpay.create(:subscriptions)
          response_hash = @subscriptions.get(openpay_subscription_id, openpay_customer_id)

          # Extract values from response
          @charge_date, @creation_date, @current_period_number, @period_end_date, @status, @trial_end_date = response_hash.values_at('charge_date', 'creation_date', 'current_period_number', 'period_end_date', 'status', 'trial_end_date')

          case @status
          when 'past_due'
            @premium = false
            @cancelled = Time.now
          when 'unpaid'
            @premium = false
            @cancelled = Time.now
          when 'cancelled'
            @premium = false
            @cancelled = Time.now
          else
            @premium = true
            @cancelled = nil
          end

        end

        # Update user payment record with response from Openpay
        @payment_method = PaymentMethod.update(
          premium: @premium,
          charge_date: @charge_date,
          creation_date: @creation_date,
          current_period_number: @current_period_number,
          period_end_date: @period_end_date,
          status: @status,
          trial_end_date: @trial_end_date,
          cancelled_on: @cancelled
        )

        puts "User #{user.email} update, Complete!"

      end
    end
  end
end

The SQL: SQL:

PaymentMethod Load (0.4ms)  SELECT `payment_methods`.* FROM `payment_methods`
   (0.1ms)  BEGIN
   SQL (0.3ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:15:13', `updated_at` = '2018-06-15 21:01:19' WHERE `payment_methods`.`id` = 1
   (11.9ms)  COMMIT
   (0.1ms)  BEGIN
  SQL (0.3ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:15:13', `updated_at` = '2018-06-15 21:01:19' WHERE `payment_methods`.`id` = 2
   (2.7ms)  COMMIT
   (0.1ms)  BEGIN
  SQL (0.2ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:15:13', `updated_at` = '2018-06-15 21:01:19' WHERE `payment_methods`.`id` = 3
   (2.6ms)  COMMIT
User medic1@mail.com update, Complete!

  PaymentMethod Load (0.3ms)  SELECT `payment_methods`.* FROM `payment_methods`
   (0.1ms)  BEGIN
   SQL (0.3ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:16:24', `updated_at` = '2018-06-15 21:01:20' WHERE `payment_methods`.`id` = 1
   (11.9ms)  COMMIT
   (0.1ms)  BEGIN
  SQL (0.3ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:16:24', `updated_at` = '2018-06-15 21:01:20' WHERE `payment_methods`.`id` = 2
   (2.7ms)  COMMIT
   (0.1ms)  BEGIN
  SQL (0.3ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:16:24', `updated_at` = '2018-06-15 21:01:20' WHERE `payment_methods`.`id` = 3
   (2.5ms)  COMMIT
User medic2@mail.com update, Complete!

  PaymentMethod Load (0.3ms)  SELECT `payment_methods`.* FROM `payment_methods`
   (0.1ms)  BEGIN
  SQL (0.2ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:18:30', `updated_at` = '2018-06-15 21:01:22' WHERE `payment_methods`.`id` = 1
   (2.6ms)  COMMIT
   (0.1ms)  BEGIN
  SQL (0.2ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:18:30', `updated_at` = '2018-06-15 21:01:22' WHERE `payment_methods`.`id` = 2
   (2.6ms)  COMMIT
   (0.1ms)  BEGIN
  SQL (0.3ms)  UPDATE `payment_methods` SET `creation_date` = '2018-06-15 19:18:30', `updated_at` = '2018-06-15 21:01:22' WHERE `payment_methods`.`id` = 3
   (2.6ms)  COMMIT
User medic4@mail.com update, Complete!

Models: 楷模:

class Medic < ApplicationRecord
  has_many :payment_methods, dependent: :destroy
end

class PaymentMethod < ApplicationRecord
  belongs_to :medic, optional: true 
end

Thanks for your answers, they finally helped me to realize that I have to update each object, so I did it by going through PaymentMethod.where(id: @subscription_id, medic_id: @medic_id).update() 感谢您的回答,他们终于帮助我意识到我必须更新每个对象,因此我通过PaymentMethod.where(id: @subscription_id, medic_id: @medic_id).update()做到了这一点。

namespace :premium_users do
  desc 'Get the user id & data in a hash'
  task get_users: :environment do 
    # Get the user and association payment_method where period_end_date not nil, means that this user has a payment_method
    users = Medic.includes(:payment_methods).where.not payment_methods: { period_end_date: nil }
    request_hash = {}

    users.each do |user|
      # Set to compare period end date with date today 
      period_end_date = user.payment_methods.last.period_end_date

      # Create a user hash if period_end_date is 2 days from date today
      if Date.today - period_end_date <= 172_800
        medic_id, subscription_id, openpay_customer_id, openpay_subscription_id = user.payment_methods.last.medic_id, user.payment_methods.last.id, user.payment_methods.last.openpay_customer_id, user.payment_methods.last.openpay_subscription_id
        user_hash = {}
        user_hash[medic_id] = [subscription_id, openpay_customer_id, openpay_subscription_id]
      else
        user_hash = {} 
      end

      request_hash.merge!(user_hash) # If no users is empty => {}

      if request_hash.empty?
        puts 'No User to check!'
      else
        request_hash.each do |key, value|
          @medic_id, @subscription_id, openpay_customer_id, openpay_subscription_id = key, value[0], value[1], value[2]

          # Openpay API connection and request
          @openpay = OpenpayApi.new(ENV['MERCHANT_ID_OPENPAY'], ENV['SECRET_KEY_OPENPAY'])
          @subscriptions = @openpay.create(:subscriptions)
          # @subscriptions.get(subscription_id,customer_id)
          response_hash = @subscriptions.get(openpay_subscription_id, openpay_customer_id)

          # Split values
          @charge_date, @creation_date, @current_period_number, @period_end_date, @status, @trial_end_date = response_hash.values_at('charge_date', 'creation_date', 'current_period_number', 'period_end_date', 'status', 'trial_end_date')

          # Status conditions
          case @status
          when 'past_due'
            @premium = false
            @cancelled = Time.now
          when 'unpaid'
            @premium = false
            @cancelled = Time.now
          when 'cancelled'
            @premium = false
            @cancelled = Time.now
          else
            @premium = true
            @cancelled = nil
          end
        end

        # Update each subscription with data from API response
        @payment_method = PaymentMethod.where(id: @subscription_id, medic_id: @medic_id).update(
          premium: @premium,
          charge_date: @charge_date,
          creation_date: @creation_date,
          current_period_number: @current_period_number,
          period_end_date: @period_end_date,
          status: @status,
          trial_end_date: @trial_end_date,
          cancelled_on: @cancelled
        )

        puts "User #{@medic_id} update, Complete!"
      end
    end
  end
end

Result: 结果:

PaymentMethod Load (0.5ms)  SELECT `payment_methods`.* FROM `payment_methods` WHERE `payment_methods`.`id` = 1 AND `payment_methods`.`medic_id` = 1
   (0.2ms)  BEGIN
  SQL (0.4ms)  UPDATE `payment_methods` SET `premium` = 1, `current_period_number` = 0, `status` = 'trial', `updated_at` = '2018-06-20 17:40:20' WHERE `payment_methods`.`id` = 1
   (12.1ms)  COMMIT
User 1 update, Complete!
  PaymentMethod Load (0.5ms)  SELECT `payment_methods`.* FROM `payment_methods` WHERE `payment_methods`.`id` = 2 AND `payment_methods`.`medic_id` = 3
   (0.2ms)  BEGIN
  SQL (0.4ms)  UPDATE `payment_methods` SET `premium` = 1, `status` = 'trial', `cancelled_on` = NULL, `updated_at` = '2018-06-20 17:40:22' WHERE `payment_methods`.`id` = 2
   (11.8ms)  COMMIT
User 3 update, Complete!
  0.040000   0.010000   0.050000 (  1.741126)

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

相关问题 从多个相同的记录中仅更新DB2中的1条记录? - Update only 1 record in DB2 from multiple identical records? 如何将具有相同 id 的多条记录的表重塑为每个 id 一条记录的表而不会丢失信息? - How to reshape a table having multiple records for the same id into a table with one record per id without losing information? 查看多个记录,其中每个发票合计预计有一个记录-SQL Server - Seeing multiple records where one record per invoice is expected in an aggregate - SQL Server 表中每个条件更新一条记录 - Update ONE record per condition in a table SQL更新,每条记录有多个更新 - SQL Update with Multiple updates per Record 根据符合条件的 1 条记录更新多条记录 - Update multiple records based on 1 record meeting a criteria 使用多个线程进行数据库更新会导致每次更新的写入时间更长 - Using multiple threads for DB updates results in higher write time per update 从另一个表返回单个记录,每个事务具有多个记录 - Return single record from another table with multiple records per transactionDate 返回多条记录,但每个相似条件应限制 1 条记录 - Return multiple records, but it should limit 1 record per each similar condition 从多条记录中返回一条记录 - Return one record from multiple records
 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM