从列表中删除多个空格

Question

Given list:

>>> l1 = ['1,  A Ab','2,B Bc ','3, C Cd ']

1. First element is having 2 spaces before A Ab .
2. Second element is having 1 space after B Bc .
3. Third element is 1 space each side of C Cd .

Want to remove n numbers of spaces occures before/after the element values.

Expected Result:

['1,A Ab','2,B Bc','3,C Cd']

My try:

>>> import re
>>> l2 = [re.sub(r"\s{2,}", "", s) for s in l1]
>>> l2
['1,A Ab', '2,B Bc ', '3, C Cd ']

Still getting spaces in second and third element.

Answer 1

Using a list comprehension.

Ex:

l1 = ['1,  A Ab','2,B Bc ','3, C Cd ']
print( [",".join(map(str.strip, i.split(","))) for i in l1] )

Output:

['1,A Ab', '2,B Bc', '3,C Cd']

Answer 2

Try this. it uses list comprehension .

>>> l1 = ['1,  A Ab','2,B Bc ','3, C Cd ']
>>>
>>> l1 = [",".join([s.strip() for s in item.split(",")]) for item in l1]
>>>
>>> l1
['1,A Ab', '2,B Bc', '3,C Cd']
>>>

Answer 3

Another way to achieve the same,

import re
l1 = ['1,  A Ab','2,B Bc ','3, C Cd ']
new_list = [re.sub(', +',',', i).strip() for i in l1]

Output

['1,A Ab', '2,B Bc', '3,C Cd']

Answer 4

Try it:

import re
l1 = ['1,  A Ab','2,B Bc ','3, C Cd ']
l2 = [re.sub(r"\s{2,}|(?<=,)\s|\s$","",s) for s in l1]
l2