使用各种参数在C＃中从cmd.exe运行.bat文件

Question

I've been trying all day to start process which would run the following code:

C:\\bin\\ant.bat -f=C:\\build.xml -DinputFile=C:\\Desktop\\Book1.xml -DstartDate=2018-06-20 -DxslFile=ProcessingDate -DoutputFile=fff

and it works completely fine in cmd .

this is my last code in C# which I really hoped would work, but however it doesn't:

public void run() {
        string antFile = @"C:\ant.bat";
        string build = @"C:\build.xml";
        string inputFile = @"C:\Book1.xml";
        string startDate = "2018-05-23";
        string outputFile = "ff";
        ProcessStartInfo procStartInfo = new ProcessStartInfo("cmd.exe", "/c" + @"C:bin\ant.bat -f=C:\build.xml -DinputFile=C:\Desktop\Book1.xml -DstartDate=2018-06-20 -DxslFile=ProcessingDate -DoutputFile=test0.xsl");
        Process proc = new Process();
        proc.StartInfo = procStartInfo;
        proc.Start();

        ProcessStartInfo procStartInfo2 = new ProcessStartInfo("cmd.exe", "/c" + antFile + "-f=" + build + "-DinputFile=" + inputFile + "-DstartDate=" + startDate + "-DxslFile=" + startDate + "-DoutputFile=" + outputFile);
        Process proc2 = new Process();
        proc2.StartInfo = procStartInfo2;
        proc2.Start();
    }

Firstly, I've tried to just put everything from cmd to the process but it didn't work, after I tried to do what I actually have to: put all the string values as arguments but it didn't work either.

Instead I am getting bunch of exceptions

I'm literally out of options as I've sat all day doing this. Does anyone have idea what problem it could be?

UPDATE:

I've managed to run startInfo3 process. But startInfo4 still doesn't work. I've checked both lines seem to produce the same so what's wrong with it if they're are the same. Do I pass them incorrectly?

           ProcessStartInfo startInfo3 = new ProcessStartInfo();
            startInfo3.FileName = "cmd.exe";
            startInfo3.Arguments = "/c" + @"C:\ant.bat -f=C:\build.xml -DinputFile=C:\Book1.xml -DstartDate=2018-06-20 -DxslFile=ProcessingDate -DoutputFile=fff";
            Process.Start(startInfo3);

            ProcessStartInfo startInfo4 = new ProcessStartInfo();
            startInfo4.FileName = "cmd.exe";
            startInfo4.Arguments = "/c" + antFile + "-f=" + build + "-DinputFile=" + inputFile + "-DstartDate=" + startDate + "-DxslFile=" + startDate + "-DoutputFile=" + outputFile;
            Process.Start(startInfo4);

Answer 1

After digging a bit more I figured out an answer:

ProcessStartInfo procStartInfo5 = new ProcessStartInfo();
            procStartInfo5.FileName = "cmd.exe";
            procStartInfo5.Arguments = $"/c{antFile} -f={build} -DinputFile={inputFile} -DstartDate={startDate} -DxslFile=ProcessingDate -DoutputFile={outputFile}";
            Process.Start(procStartInfo5);

Hope it helps someone!