[英]javascript variable doesn't show validation errors of codeigniter in the form
i'm using ci built-in validation_errors() function in my login form. 我在登录表单中使用ci内置的validate_errors()函数。 everything works fine and i can see true validation errors in my view.
一切正常,我可以在视图中看到真正的验证错误。 but when i echo validation errors into my js variable in the script to show it in the customized notifications, nothing shows.
但是,当我在脚本中将验证错误回显到我的js变量中以在自定义通知中显示该错误时,什么也没有显示。 here is my code:
这是我的代码:
<?php if (isset($validation_error)){
echo $validation_error;} ?>
<script>
var text= "<?php echo $validation_error;?>";
</script>
<script src="<?php echo base_url();?>resources/js/assets/errore-not.js" type="text/javascript">
</script>
when i pass any php variables or strings in "text" variable of script, it shows the notification correctly. 当我在脚本的“文本”变量中传递任何php变量或字符串时,它会正确显示通知。 this is my notify code:
这是我的通知代码:
$(document).ready(function notification () {
$.notify({
icon: "notifications",
message: text
}, {
type: 'danger',
timer: 4000,
placement: {
from: 'top',
align: 'center'
}
});
});
How can I do this? 我怎样才能做到这一点?
You can pass the php variable value inside javascript variable like this. 您可以像这样在javascript变量内传递php变量值。
<?php if (isset($validation_error)){
echo $validation_error; ?>
<script>
var text= '<?php echo $validation_error;?>';
</script>
<?php } ?>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.