使用文件夹的名称重命名文件夹中的所有图像

Question

I have a lot of folders. in each folder, there is an image. I want to rename all of the images with the name of its folder.

For example: Folder "1" has an image "273.jpg" I want to change it into the "1.jpg" and save it in another directory.

This is what I have done so far:

import os
import pathlib

root = "Q:/1_Projekte/2980/"

for path, subdirs, files in os.walk(root):
    for name in files:
        print (pathlib.PurePath(path, name))
        os.rename(os.path.join(path, name), os.path.join(path, os.path.basename(path)))
        print(os.path.basename(path))

The problem is that it works just for the first folder, then it jumps out with the error:

this file is already available...

the tree of folders and the images are like this:

Q:/1_Projekte/2980/1/43425.jpg

Q:/1_Projekte/2980/2/43465.jpg

Q:/1_Projekte/2980/3/43483.jpg

Q:/1_Projekte/2980/4/43499.jpg

So there is just one file in each directory!

Answer 1

Probably you have some hidden files in those directories. Check it out. If those files are not jpg , you can use following code:

for path, subdirs, files in os.walk(root):
    for name in files:
        extension = name.split(".")[-1].lower()
        if extension != "jpg":
            continue
        os.rename(os.path.join(path, name), os.path.join(path, os.path.basename(path) + "." + extension))
        print(os.path.basename(path))

This code extracts the extension of the file and checks if it is equal to the jpg . If file extension is not jpg , so continue statement will run and next file will check. If file type is jpg , script renames it. Also this code adds original file extension to the new name. Previous code didn't handle that. I hope this helpe you.

Answer 2

Maybe this might help...

import os

root = "Q:/1_Projekte/2980/"
subdirs = [x for x in os.listdir(root) if os.path.isdir(x)]

for dir_name in subdirs:
    dir_path = root + dir_name + '/'
    files = os.listdir(dir_path)

    print(dir_name)
    print(files)

    for i in files:
        counter = 1
        extension = i.split('.')[-1]
        new_name = dir_name + '.' + extension

        while True:
            try:
                os.rename(dir_path + i, dir_path + new_name)
                break

            except:
                # If the file exists...
                new_name = dir_name + '({})'.format(counter) + '.' + extension
                counter += 1

This code ensures that even if a file with the existing name happens to exist, it will be suffixed with a number in brackets.