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dplyr mutate问题案例

[英]dplyr mutate issue case when

I have the following data: 我有以下数据:

d <- data.frame(
        ID= c("NULL", "NULL", "1232", "4565", "4321"))

I'm trying to create a new line that shows "missing" when the ID is NULL, and "not missing" when the ID is not NULL. 我试图创建一个新行,当ID为NULL时显示“丢失”,而当ID不为NULL时显示“不丢失”。 I have the following code: 我有以下代码:

d %>%
mutate(ID_missing= case_when(ID=="NULL") ~ "missing", 
                           ID!="NULL" ~ "not missing", TRUE ~ NA_real_) -> d

however I get the following error: 但是我得到以下错误:

Error in mutate_impl(.data, dots) : 
Column `name_of` is of unsupported type quoted call

I can't see any guidance on line and I can't see what might be wrong with my code. 我看不到任何指导,也看不到我的代码可能有什么问题。 Any ideas? 有任何想法吗?

There are two problems in your approach: 您的方法存在两个问题:

1) parenthesis 1)括号

Your use of case_when is incorrect because of the closing parenthesis in the middle of the function. 您使用的case_when不正确,因为该函数中间的case_when括号是。 It should be 它应该是

case_when(ID=="NULL" ~ "missing", 
          ID!="NULL" ~ "not missing", 
          TRUE       ~ NA_real_))

2) Incorrect NA-type 2)不正确的NA类型

You're using NA_real_ inside a character column. 您正在字符列内使用NA_real_ You need to use NA_character_ instead. 您需要改用NA_character_

The final would then be: 最终将是:

d %>%
    mutate(ID_missing= case_when(ID=="NULL" ~ "missing", 
           ID!="NULL" ~ "not missing", TRUE ~ NA_character_)) -> d

#     ID  ID_missing
# 1 NULL     missing
# 2 NULL     missing
# 3 1232 not missing
# 4 4565 not missing
# 5 4321 not missing

Below would work . 下面会工作。

require(dplyr)
d <- data.frame(
ID= c("NULL", "NULL", "1232", "4565", "4321"))

#### USE mutate and ifelse 

d <- d %>% mutate(ID_missing = ifelse(ID == "NULL","missing","not_missing"))

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