修改Java中的a.txt文件

Question

I have a text file that I want to edit using Java. It has many thousands of lines. I basically want to iterate through the lines and change/edit/delete some text. This will need to happen quite often.

From the solutions I saw on other sites, the general approach seems to be:

• Open the existing file using a BufferedReader
• Read each line, make modifications to each line, and add it to a StringBuilder
• Once all the text has been read and modified, write the contents of the StringBuilder to a new file
• Replace the old file with the new file

This solution seems slightly "hacky" to me, especially if I have thousands of lines in my text file.

Anybody know of a better solution?

Answer 1

I haven't done this in Java recently, but writing an entire file into memory seems like a bad idea.

The best idea that I can come up with is open a temporary file in writing mode at the same time, and for each line, read it, modify if necessary, then write into the temporary file. At the end, delete the original and rename the temporary file.

If you have modify permissions on the file system, you probably also have deleting and renaming permissions.

Answer 2

if the file is just a few thousand lines you should be able to read the entire file in one read and convert that to a String.

You can use apache IOUtils which has method like the following.

public static String readFile(String filename) throws IOException {
    File file = new File(filename);
    int len = (int) file.length();
    byte[] bytes = new byte[len];
    FileInputStream fis = null;
    try {
        fis = new FileInputStream(file);
        assert len == fis.read(bytes);
    } catch (IOException e) {
        close(fis);
        throw e;
    }
    return new String(bytes, "UTF-8");
}

public static void writeFile(String filename, String text) throws IOException {
    FileOutputStream fos = null;
    try {
        fos = new FileOutputStream(filename);
        fos.write(text.getBytes("UTF-8"));
    } catch (IOException e) {
        close(fos);
        throw e;
    }
}

public static void close(Closeable closeable) {
    try {
        closeable.close();
    } catch(IOException ignored) {
    }
}

Answer 3

如果文件很大，你可能想要使用FileStream进行输出，但这看起来非常像是你所要求的最简单的过程（没有更多的特殊性，即你做什么类型的更改/编辑/删除）我试图做，不可能确定哪种更复杂的方式可行。

Answer 4

No reason to buffer the entire file.

Simply write each line as your read it, insert lines when necessary, delete lines when necessary, replace lines when necessary.

Fundamentally, you will not get around having to recreate the file wholesale, especially if it's just a text file.

Answer 5

What kind of data is it? Do you control the format of the file?

If the file contains name/value pairs (or similar), you could have some luck with Properties , or perhaps cobbling together something using a flat file JDBC driver.

Alternatively, have you considered not writing the data so often? Operating on an in-memory copy of your file should be relatively trivial. If there are no external resources which need real time updates of the file, then there is no need to go to disk every time you want to make a modification. You can run a scheduled task to write periodic updates to disk if you are worried about data backup.

Answer 6

Although this question was a time ago posted, I think it is good to put my answer here. I think that the best approach is to use FileChannel from java.nio.channels package in this scenario. But this, only if you need to have a good performance! You would need to get a FileChannel via a RandomAccessFile , like this:

java.nio.channels.FileChannel channel = new java.io.RandomAccessFile("/my/fyle/path", "rw").getChannel();

After this, you need a to create a ByteBuffer where you will read from the FileChannel .

this looks something like this:

java.nio.ByteBuffer inBuffer = java.nio.ByteBuffer.allocate(100);
int pos = 0;
int aux = 0;
StringBuilder sb = new StringBuilder();

while (pos != -1) {

    aux = channel.read(inBuffer, pos);
    pos = (aux != -1) ? pos + aux : -1;

    b = inBuffer.array();
    sb.delete(0, sb.length());

    for (int i = 0; i < b.length; ++i) {

         sb.append((char)b[i]);

    }

    //here you can do your stuff on sb

    inBuffer = ByteBuffer.allocate(100);

}

Hope that my answer will help you!

Answer 7

我认为， FileOutputStream.getFileChannel()会有很多帮助，请参阅FileChannel api http://java.sun.com/javase/6/docs/api/java/nio/channels/FileChannel.html

Answer 8

You can use RandomAccessFile in Java to modify the file on one condition: The size of each line has to be fixed otherwise, when new string is written back, it might override the string in the next line.

Therefore, in my example, I set the line length as 100 and padding with space string when creating the file and writing back to the file.

So in order to allow update, you need to set the length of line a little larger than the longest length of the line in this file.

public class RandomAccessFileUtil {
public static final long RECORD_LENGTH = 100;
public static final String EMPTY_STRING = " ";
public static final String CRLF = "\n";

public static final String PATHNAME = "/home/mjiang/JM/mahtew.txt";

/**
 *  one two three
    Text to be appended with
    five six seven
    eight nine ten
 * 
 * 
 * @param args
 * @throws IOException
 */
public static void main(String[] args) throws IOException
{
    String starPrefix = "Text to be appended with";
    String replacedString = "new text has been appended";

    RandomAccessFile file = new RandomAccessFile(new File(PATHNAME), "rw");

    String line = "";
    while((line = file.readLine()) != null)
    {
        if(line.startsWith(starPrefix))
        {
            file.seek(file.getFilePointer() - RECORD_LENGTH - 1);
            file.writeBytes(replacedString);
        }

    }
}

public static void createFile() throws IOException
{
    RandomAccessFile file = new RandomAccessFile(new File(PATHNAME), "rw");

    String line1 = "one two three";
    String line2 = "Text to be appended with";
    String line3 = "five six seven";
    String line4 = "eight nine ten";

    file.writeBytes(paddingRight(line1));
    file.writeBytes(CRLF);
    file.writeBytes(paddingRight(line2));
    file.writeBytes(CRLF);
    file.writeBytes(paddingRight(line3));
    file.writeBytes(CRLF);
    file.writeBytes(paddingRight(line4));
    file.writeBytes(CRLF);

    file.close();

    System.out.println(String.format("File is created in [%s]", PATHNAME));
}

public static String paddingRight(String source)
{
    StringBuilder result = new StringBuilder(100);
    if(source != null)
    {
        result.append(source);
        for (int i = 0; i < RECORD_LENGTH - source.length(); i++)
        {
            result.append(EMPTY_STRING);
        }
    }

    return result.toString();
}

}

Answer 9

In general you cannot edit the file in place; it's simply a very long sequence of characters, which happens to include newline characters. You could edit in place if your changes don't change the number of characters in each line.

Answer 10

Can't you use regular expressions, if you know what you want to change ? Jakarta Regexp should probably do the trick.

Answer 11

private static void modifyFile(String filePath, String oldString, String newString) {
    File fileToBeModified = new File(filePath);
    StringBuilder oldContent = new StringBuilder();
    try (BufferedReader reader = new BufferedReader(new FileReader(fileToBeModified))) {
        String line = reader.readLine();
        while (line != null) {
            oldContent.append(line).append(System.lineSeparator());
            line = reader.readLine();
        }
        String content = oldContent.toString();
        String newContent = content.replaceAll(oldString, newString);
        try (FileWriter writer = new FileWriter(fileToBeModified)) {
            writer.write(newContent);
        }
    } catch (IOException e) {
        e.printStackTrace();
    }
}

Answer 12

您可以通过单击“另存为”并保存* .java扩展名保存，将txt文件更改为java。