[英]Notepad++ Find and replace using regex
I need to trim a single whitespace in a large txt file using regex within Notepad++'s find and replace function. 我需要在Notepad ++的查找和替换功能中使用正则表达式来修剪大型txt文件中的单个空格。
The pattern is: 模式是:
06.01.001.01.04
Including the space after the 4. All entries follow the same pattern of 2 numbers, dot 2 numbers dot, 3 numbers dot, 2 numbers dot, 2 numbers. 包括4后面的空格。所有条目都遵循相同的模式,即2个数字,2个点,3个点,2个点,2个数字。 There is no dot before or after the numbers.
在数字之前或之后没有点。
My understanding is that I can replace the value found with the found value but with the following space removed. 我的理解是,我可以将找到的值替换为找到的值,但要删除以下空格。
Find (\\.\\d{2})\\s
查找
(\\.\\d{2})\\s
Replace $1
替换
$1
If you have more numbered format, make it more explicit: 如果您有更多编号的格式,请使其更明确:
Find (\\d{2}\\.\\d{2}\\.\\d{3}\\.\\d{2}\\.\\d{2})\\s
查找
(\\d{2}\\.\\d{2}\\.\\d{3}\\.\\d{2}\\.\\d{2})\\s
Following may help you here. 以下内容可能会对您有所帮助。
Place in find following regex: 放在查找以下正则表达式中:
([0-9]{2}\.[0-9]{2}\.[0-9]{3}\.[0-9]{2}\.[0-9]{2})\s+
Place following in replace: 将以下内容替换:
$1\n
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