通过python regex忽略IP地址的第一个八位字节中的这两个数字（以127或0开头）

Question

I have a list of IP's stored in a text file along with some other data from which I am trying to grep only the valid IP's. Here, I have some IP's like 0.0.0.0 and localhost IP's (starts with 127...) which I am trying to eliminate using regex. Here is the regex pattern I came up with that filters 0.0.0.0 IP's but couldn't effectively remove the 127..* IP's.

import re
with open("data","r") as f:
    for line in f:
        test = re.search(r'(?!0|127)\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}', line)
        if test:
            print(test.group(0))

The IP's are in the text file like this:

127.3.65.7
alkjgfbvui vluiybr vk ru r127.0.0.1fal;iufnaw  waoun
12.0.1.5
mjhgvjg0.0.0.0kjuycuj
0.0.0.0
0.0.0.0
gare bloing r pgnao wyin212.2.174.64
207.71.31.224
awuie nvp; vwa rv;awiu n ;lkirjght94.206.93.104ta;wourit mrt'
172.20.128.1
172.20.164.207
172.20.164.203
172.20.164.209
1.8.0.144

I am getting the following output where you can see IP's that starts with 127 is also printed by just removing the first digit '1'

27.3.65.7
27.0.0.1
12.0.1.5
212.2.174.64
207.71.31.224
94.206.93.104
172.20.128.1
172.20.164.207
172.20.164.203
172.20.164.209
1.8.0.144

Answer 1

Try Regex: (?<!\\d)(?!0|127)\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}\\.\\d{1,3}

Demo

Explanation:

Add a negative look behind for \\d to eliminate matches starting with 27