扩展Python类的init方法

Question

I have a BaseClass and an AbstractClass that inherits from the BaseClass . This is the structure I have in place

class BaseClass(object):
    def __init__(self, initialize=True):
        self.name = 'base_class'
        self.start = 0
        if initialize:
            self.start = 100

class AbstractClass(BaseClass):
    def __init__(self):
        self.name = 'asbtract_class'
        super(BaseClass, self).__init__()

I want to pass the abstract class an initialize parameter that gets transferred to the base class and if True sets the object's start value to 100 .

I tried using the super(BaseClass, self).__init__() but the abstract class gets no start attribute. I get an error when I try to access it.

How can I pass a value the initialize argument to the AbstractClass and use the BaseClass 's __init__ method to set the start attribute on the AbstractClass .

The code I used

best = BaseClass()
abs = AbstractClass()
abs.start # AttributeError: 'AbstractClass' object has no attribute 'start'

Answer 1

To invoke the constructor of the super class you should use the class name of the sub class and not the super class, ie:

class AbstractClass(BaseClass):
    def __init__(self):
        super(AbstractClass, self).__init__()
        self.name = 'abstract_class'

Note also that I changed the order of invoking the constructor of the super class and setting the name attribute. If you set it before calling the super, the attribute would be overridden by the constructor of the super class, which is most likely not what you intended

And as @Sraw pointed out, for python 3 the notation of calling the super no longer requires the referencing of the class name and can be simplified to

class AbstractClass(BaseClass):
    def __init__(self):
        super().__init__()