如果知道对象的属性等同于该对象，该如何确定它的名称？

Question

I am working on a JavaScript program that helps you encrypt and decrypt messages. In order to make it very secure, I am planning on creating an object that contains the properties of id and text . Here is an example object:

var object1 = {
    id: "AE309JKL36784AJBCMDH"
    text: "∆∂˙˚∆ƒ˙ø©ˆ´¨¬˚å˙∂©¬˚"
}

Let's say I know that text is equal to ∆∂˙˚∆ƒ˙ø©ˆ´¨¬˚å˙∂©¬˚ . How am I able to figure out that the name of the object that has this value for the property of text is object1 ?

Thank in advance.

Answer 1

It depends on the scope , where you declare your var , so I would rather use this (which will also work for window case):

var object1 = {
  id:  "AE309JKL36784AJBCMDH",
  text: "∆∂˙˚∆ƒ˙ø©ˆ´¨¬˚å˙∂©¬˚"
};

console.log(Object.keys(this).find(k => this[k] && this[k].text && this[k].text === '∆∂˙˚∆ƒ˙ø©ˆ´¨¬˚å˙∂©¬˚'));

@Dave Newton is absolutely right, this answer will not work for example in this case:

(function(){
  var object1 = {
    id:  "AE309JKL36784AJBCMDH",
    text: "∆∂˙˚∆ƒ˙ø©ˆ´¨¬˚å˙∂©¬˚"
  };

  console.log(Object.keys(this).find(k => this[k] && this[k].text &&     this[k].text === '∆∂˙˚∆ƒ˙ø©ˆ´¨¬˚å˙∂©¬˚'));
}())

where this will be calling scope window

Answer 2

Object.keys(window).find((key) => {
    let obj = window[key];
    return obj && typeof obj === "object" && obj.text && obj.id && obj.text === "∆∂˙˚∆ƒ˙ø©ˆ´¨¬˚å˙∂©¬˚";
});