出现逻辑错误时，将打印出三个或五个整数的所有数字之和

Question

I'm having some logic errors with my program. I've been trying to solve this for the last couple of hours. It's supposed to print the sum of all the numbers that are either multiple of three or five.

my output

1.)enter an integer number (0 to end): enter an integer number (0 to end):
2.)enter an integer number (0 to end): 3+ = 3

expected output

1.)enter an integer number (0 to end): 3 = 3
2.)enter an integer number (0 to end): 3+5 = 8

below is my code.

while True:
  answer = ""
  num = int(input("enter an integer number (0 to end): "))
  end_answer = 0

  if num == 0:
    exit()

  for i in range(1, num+1):
    if i%3==0 or i%5==0 :
      answer += str(i)
      end_answer += i


    if i != num and (i%3==0 or i%5==0):
      answer += "+"
      print(str(answer) + " = " + str(end_answer) )

I've seen similar answers for this just not in python specifically

Answer 1

The following (properly indented) code will give you what you need:

while True:
    num = int(input('Enter an integer number (0 to end): '))
    if num == 0: exit()

    answer = ''
    end_answer = 0
    sep = ''
    for i in range(1, num+1):
        if i % 3 == 0 or i % 5 == 0 :
            answer += sep + str(i)
            sep = ' + '
            end_answer += i

    if end_answer > 0:
        print(str(answer) + ' = ' + str(end_answer) )

Note that it uses a variable separator sep to more cleanly print the item you're working out. A sample run follows:

Enter an integer number (0 to end): 2
Enter an integer number (0 to end): 3
3 = 3
Enter an integer number (0 to end): 10
3 + 5 + 6 + 9 + 10 = 33
Enter an integer number (0 to end): 38
3 + 5 + 6 + 9 + 10 + 12 + 15 + 18 + 20 + 21 + 24 + 25 + 27 + 30 + 33 + 35 + 36 = 329
Enter an integer number (0 to end): 0

Answer 2

You can simplify your code a lot by using the sum builtin and f-strings for printed text formatting. This will likely be more efficient as well.

Code

from itertools import count

counter = count(1)

while True:
    num = int(input(f'{next(counter)}). Enter an integer number (0 to end): '))

    if num == 0:
        break

    nums = [x for x in range(1, num + 1) if x % 3 == 0 or x % 5 == 0]
    print(f'{" + ".join(map(str, nums))} = {sum(nums)}')

Output

1). Enter an integer number (0 to end): 3
3 = 3
2). Enter an integer number (0 to end): 9
3 + 5 + 6 + 9 = 23
3). Enter an integer number (0 to end): 15
3 + 5 + 6 + 9 + 10 + 12 + 15 = 60
4). Enter an integer number (0 to end): 0