如何在Linux bash中如何检查脚本文件是否存在并在一个衬套中执行

Question

I have many scripts in different directories , i want to check if those script file exist and then execute them in one liner in shortest way .
there is the simple way :

if [ -f /A/B/C/foo.sh ]; then /A/B/C/foo.sh

can i shorten this one liner ?

Answer 1

Simply use

/A/B/C/foo.sh

The bash will check if this script file exists and then execute it. If the script does not exist, it will report

bash: /A/B/C/foo.sh: No such file or directory

Alternatively, you can suppress the error message with

/A/B/C/foo.sh 2> /dev/null

As others suggested, you can also check the script existence on your own using

[ -x /A/B/C/foo.sh ] && /A/B/C/foo.sh

Note the -x instead of -f (tests if the file is executable).

If you have many scripts in different directories, you can execute them using the following one-liner:

for f in /A/B/C/foo.sh /D/E/F/bar.sh; do [ -x "$f" ] && "$f"; done

Answer 2

You can use a function like this:

run() { [[ -x $1 ]] && "$@"; }

And then use function as:

run '/A/B/C/foo.sh'
run '/A/B/C/bar.sh'

Answer 3

[ -f /A/B/C/foo.sh ] && /A/B/C/foo.sh

The && is a C-like and . If the command on the left return true, execute the command on the right.

Answer 4

Try bash test command :

And how it's works.

$ cat src.sh
echo "Test test"

//if src.sh exist
$test -e src.sh && sh src.sh
Test test

// if not, src.sh not run
$test -e src1.sh && sh src.sh

Answer 5

是的，可以使用速记格式将其进一步缩短：

[ -f /A/B/C/foo.sh ] && /A/B/C/foo.sh || echo "script not found"