如何将数组拆分为具有交替元素的两个数组

Question

I want to split an array of strings into two arrays. However, when I push the strings into the new arrays, it should be alternating. So, if the array is:

let alph = [a,b,c,d,e,f]

Then the new arrays would look like:

firstArr = [a,c,e]
secondArr = [b,d,f]

How can I do it so I'm not repeating myself? I have the following code, and it works, but I do not want to write two of the same filter functions (keep things DRY):

let firstArr = alph.filter((letter, index) => {
  return index % 2 === 0;
})

Answer 1

You could take an array of the both arrays and take the index as indicator for the wanted array for pushing.

 let alph = ['a', 'b', 'c', 'd', 'e', 'f'], first = [], second = [], temp = [first, second]; alph.forEach((v, i) => temp[i % 2].push(v)); console.log(first); console.log(second); 

Answer 2

Since filter creates one array, you need two, or use eg forEach

 var arr = ["a","b","c","d","e","f"], firstArr = [], secondArr = []; arr.forEach( (a,i) => { (i % 2 === 0) ? firstArr.push(a) : secondArr.push(a); }) console.log(firstArr) console.log(secondArr) 

Answer 3

For better readability there's nothing wrong with having separate filter functions for these. To clean it up a little you could use arrow functions and make them 1 liners and then pass them in the filter function, like:

const alpha = ['a', 'b', 'c', 'd', 'e', 'f'];
const filterByEvens = (letter, index) => index % 2 === 0;
const filterByOdds = (letter, index) => index % 2 !== 0;
const evens = alpha.filter(filterByEvens);
const odds = alpha.filter(filterByOdds);

Answer 4

you can use reduce for this :

 const alph = ['a', 'b', 'c', 'd', 'e', 'f']; const result = alph.reduce((acc, letter, ndx) => { acc[ndx % 2] = acc[ndx % 2] || []; acc[ndx % 2].push(letter); return acc; }, []); const [firstArr, secondArr] = result; console.log(firstArr, secondArr);