查找包含特定年份的第一个日期

Question

I'm trying to build a MATCH formula (or a similar one) that returns the position of the first value (date) within a range that matches a specific year.

For example, if I have a list of dates, like this:

      A
1 12-31-2014
2 11-30-2015
3 12-29-2016
4 12-30-2017

For the value 2016, it should return 3.

MATCH(2016,A:A,0) doesn't work, since it's not an exact match. I can't use any aux columns either nor modify the dates.

Any ideas?

Answer 1

Are you allowed to use array formulas? If so, it may be as simple as this:

=IFERROR(MATCH(2016,YEAR($A$1:$A$4),0),"No Match")

Remember to commit the answer using Ctrl + Shift + Enter , since it'll be an array.

You'll want to change the references within the YEAR function to match your range. By using 0 as your [match_type] parameter, you're going to get the first value in the list that has a year of 2016 .

Answer 2

For real dates, try,

=aggregate(15, 6, row($1:$999)/(year(a$1:a$999)=2016), 1)
'return the date with index as,
=index(a:a, aggregate(15, 6, row($1:$999)/(year(a$1:a$999)=2016), 1))

If they are in ascending order you could use,

=MATCH(42369, A:A)+1
=index(a:a, MATCH(42369, A:A)+1)

For a list of strings that look like dates try,

=MATCH("*2016", A:A, 0)
=index(a:a, MATCH("*2016", A:A, 0))