[英]Regular expression to check if string has at least one and up to 3 words and more than one hashtag in python
s1 = 'Makeupby Antonia #makeup #makeupartist #makeupdolls #abhcosmetics'
s2 = 'Makeupby Antonia asia #makeup #makeupartist #makeupdolls'
s3 = 'Makeupby Antonia'
s4 = '#makeup #makeupartist #makeupdolls #abhcosmetics'
s5 = 'Makeupby Antonia asia america #makeup #makeupartist'
Regex should be able to match s1
and s2
only because normal words count is up to 3 and these have more then one hashtag. 正则表达式应该只能匹配
s1
和s2
因为普通单词数最多为3,并且这些单词具有一个以上的#标签。
I am able to select normal words using \\b(?<![#])[\\w]+
我可以使用
\\b(?<![#])[\\w]+
选择普通词
and 和
I am able to select hashtag using [#]{1}\\w+
我可以使用
[#]{1}\\w+
选择主题标签
but when I combine the expression then it does work. 但是当我组合表达式时,它确实起作用。
How can I make final regex using these individual regex which can also track count? 我如何使用也可以跟踪计数的单个正则表达式制作最终的正则表达式?
Split the text into words and count how many of them start with a hash sign. 将文本拆分为单词,并计算其中有多少以井号开头。
def check(text):
words = text.split()
num_hashtags = sum(word.startswith('#') for word in words)
num_words = len(words) - num_hashtags
return 1 <= num_words <= 3 and num_hashtags > 1
>>> [check(text) for text in [s1,s2,s3,s4]]
[True, True, False, False]
import re
def check(text):
pattern = r'(?=.*\b(?<!#)\w+\b)(?!(?:.*\b(?<!#)\w+\b){4})(?:.*#){2}'
return bool(re.match(pattern, text))
I'm purposely not going to explain that regex because I don't want you to use it. 我故意不解释该正则表达式,因为我不希望您使用它。 That feeling of confusion you're probably feeling should be a strong sign that this is bad code.
您可能会感到困惑,这很可能表明这是错误的代码。
If I correctly understood your question and if you can assume words are always before tags you can use r'^(\\w+ ){1,3}#\\w+ #\\w+'
: 如果我正确理解了您的问题,并且可以假设单词始终位于标记之前,则可以使用
r'^(\\w+ ){1,3}#\\w+ #\\w+'
:
for s in ('Makeupby Antonia #makeup #makeupartist #makeupdolls #abhcosmetics',
'Makeupby Antonia asia #makeup #makeupartist #makeupdolls',
'Makeupby Antonia',
'#makeup #makeupartist #makeupdolls #abhcosmetics',
'Makeupby Antonia asia america #makeup #makeupartist',):
print(bool(re.search(r'^(\w+ ){1,3}#\w+ #\w+', s)), s, sep=': ')
This outputs: 输出:
True: Makeupby Antonia #makeup #makeupartist #makeupdolls #abhcosmetics
True: Makeupby Antonia asia #makeup #makeupartist #makeupdolls
False: Makeupby Antonia
False: #makeup #makeupartist #makeupdolls #abhcosmetics
False: Makeupby Antonia asia america #makeup #makeupartist
Probably a lot of room for optimization (maybe with dependencies/fewer loops) but here's a non-regex solution as discussed in comments: 可能有很大的优化空间(可能有依赖项/较少的循环),但这是非正则表达式的解决方案,如注释中所述:
s_list = [s1, s2, s3, s4]
def hashtag_words(string_list):
words = [s.split(" ") for s in string_list]
hashcounts = [["#" in word for word in wordlist].count(True) for wordlist in words]
normcounts = [len(wordlist) - hashcount for wordlist, hashcount in zip(words, hashcounts)]
sel_strings = [s for s, h, n in zip(string_list, hashcounts, normcounts) if h>1 if n in (1,2,3)]
return sel_strings
hashtag_words(s_list)
>['Makeupby Antonia #makeup #makeupartist #makeupdolls #abhcosmetics',
'Makeupby Antonia asia #makeup #makeupartist #makeupdolls']
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