[英]How to map on a array and return a object with tslint. (syntactic sugar)
map
and return a new object without having TSLint saying: map
遍历数组并返回一个新对象: This arrow function body can be simplified by omitting the curly braces and the keyword 'return', and wrapping the object literal in parentheses.
可以通过省略花括号和关键字“ return”,并将对象文字括在括号中来简化此箭头函数的主体。
For example, the object user: 例如,对象用户:
class User { constructor( public id: number, public first_name: string, public last_name: string, public gender: Date, public location: number, ) }
And when I do this : 当我这样做时:
const simple_users = users.map(u => { return { name: u.name, id: u.id} });
Then this happens : 然后发生这种情况:
\n[tslint] This arrow function body can be simplified by omitting the curly braces and the[tslint]通过省略花括号和\nkeyword 'return', and wrapping the object literal in parentheses.
关键字“ return”,并将对象文字括在括号中。 (arrow-return-shorthand)
(箭头返回简写)\n
And I want to keep the tslint rule arrow-return-shorthand
. 我想保留tslint规则
arrow-return-shorthand
。
Simply wrap your object inside ()
(parenthesis) and remove the function
and return
statement. 只需将您的对象包装在
()
(括号)中,然后删除function
和return
语句即可。 The shorthand is below. 简写如下。
const simple_users = users.map(u => ({ name: u.name, id: u.id}));
Further destructuring
version would be more shorten. 进一步的
destructuring
版本将更短。
const simple_users = users.map(({name, id}) => ({ name, id}));
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