[英]Dependant increment primary key with Entity Framework
I'm working with C#, Entity Framework 6.1.3 code-first, SQL Server for the first time, and I'm having problems creating a dependent autoincrementing key. 我第一次使用C#,Entity Framework 6.1.3代码优先,SQL Server,并且在创建依赖的自动增量键时遇到问题。
I have this: 我有这个:
class One
{
[Key]
[Required]
string exampleKey { get; set; }
string otherProperty { get; set; }
}
class Two
{
[Required]
[Key]
[Column(Order = 0 )]
public string exampleKey { get; set; }
[ForeignKey("exampleKey")]
public virtual One one { get; set; }
[Key]
[DatabaseGenerated(DatabaseGeneratedOption.Identity)]
[Column(Order = 1)]
[Required]
public long Version { get; set; }
public string otherProperty { get; set; }
}
I'm interested in the Version
property of class Two
when you insert data it make ids like 我对类
Two
的Version
属性感兴趣,当您插入数据时,它会使id像
Class One
类
One
|exampleKey|otherProperty|
|"test" |"random data"|
|"test2" |"more random"|
Class Two
类
Two
|exampleKey|Version|otherProperty|
|"test" |1 |"random data"|
|"test" |2 |"more random"|
|"test2" |3 |"random data"|
|"test2" |4 |"more random"|
But I'm looking for something like this 但是我正在寻找这样的东西
|exampleKey|Version|otherProperty|
|"test" |1 |"random data"|
|"test" |2 |"more random"|
|"test2" |1 |"random data"|
|"test2" |2 |"more random"|
I am looking for a solution to this problem a long time ago, is it possible? 很久以前,我正在寻找解决此问题的方法,这可能吗?
Thanks so, so much! 非常感谢!
Not easily, no. 不容易,不。 But you can derive which is the most recent by a datestamp or an identity column.
但是,您可以通过日期戳或标识列来得出最新的。 Then whenever you retrieve your data, simply get the row with the most recent date/identity value.
然后,每当您检索数据时,只需获取具有最新日期/标识值的行即可。
You could also write a view which surfaces the behavior I just mentioned. 您也可以编写一个视图,以显示我刚才提到的行为。
Something like this: 像这样:
Fake Data 伪数据
if object_id('dbo.Data') is not null drop table dbo.Data
create table dbo.Data
(
RID int identity(1,1) primary key clustered,
ExampleKey varchar(10),
OtherProperty varchar(100)
)
-- initial insert
insert into dbo.Data (ExampleKey, OtherProperty)
values ('test', 'Random data'), ('test2', 'more random')
-- Second insert
insert into dbo.Data (ExampleKey, OtherProperty)
values ('test', 'Random data'), ('test2', 'more random')
View Approach 查看方法
if object_id('dbo.vData') is not null drop view dbo.vData
go
create view dbo.vData
as
select
Version = row_number() over (partition by ExampleKey order by RID desc),
ExampleKey,
OtherProperty
from dbo.Data
go
select top 1000 *
from dbo.vData
Alternatives 备择方案
If you NEED to persist it in the table when it's inserted, You'll probably need a trigger (which I wouldn't recommend). 如果您需要在插入表时将其保留在表中,则可能需要一个触发器(我不建议这样做)。
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