[英]OR in ternary operator, using &&
Using the traditional if statement I can do this: 使用传统的if语句,我可以这样做:
if(a===0 || b===0) {console.log('aloha amigo')};
But when I try to do something the same thing with a ternary operator, like this: 但是,当我尝试使用三元运算符执行相同操作时,如下所示:
a===0 || b===0 && console.log('aloha amigo')
I just get errors about unexpected ||. 我只是收到有关意外||的错误。
According to this answer: Precedence: Logical or vs. Ternary operator , we can do it using 根据以下答案: 优先级:逻辑或对三元运算符 ,我们可以使用
condition1 || condition2 ? do if true : do if false
(Sorry I'm not sure how to call the ? :
symbols in this case), but I'm not sure how to get it running using &&
(It means only run the code if returned true
). (对不起,在这种情况下,我不确定如何调用
? :
符号),但是我不确定如何使用&&
使它运行(这意味着仅在返回true
运行代码)。
I created a codepen to test it easily. 我创建了一个Codepen来对其进行轻松测试。 Here's the whole code:
这是整个代码:
var a = 0;
var b = 1;
a===0 || b===0 ? console.log('Works here') : console.log('And here');
a===0 || b===0 && console.log('Doesn\'t work here');
a===0 && console.log('The && works for a single test');
Just take parenthesis to prevent operator precedence of &&
over ||
只需加上括号以防止
&&
优先于||
(a === 0 || b === 0) && console.log('aloha amigo')
Without parenthesis, you get (now with to show the precedence) a different result. 没有括号,您将获得不同的结果(现在可以使用来显示优先级)。
a === 0 || (b === 0 && console.log('aloha amigo'))
^^^^^^^ first evaluation
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ second evaluation
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