PHP MySQL-列出除information_schema，mysql外的所有数据库

Question

In my webpage I want to list all the databases available in mysql through PHP.

The following code lists all the databases:

<?php
$link = mysql_connect('localhost', 'root', 'pass123');
$res = mysql_query("SHOW DATABASES");

while ($row = mysql_fetch_assoc($res)) {
    echo $row['Database'] . "\n";
}
?>

However, I want to exclude 'information_schema', 'mysql' and 'performance_schema' from the list of databases.

At mysql terminal, I tried:

show schema_name as database from information_schema.SCHEMATA where schema_name NOT IN ('information_schema','mysql');

but getting errors....unknown column name schema_name.

Answer 1

Just exclude from the php side like below.

$link = mysql_connect('localhost', 'root', 'pass123');
$res = mysql_query("SHOW DATABASES");

$exclude_db = array('information_schema', 'mysql', 'performance_schema');
while ($row = mysql_fetch_assoc($res)) {
    if(!in_array($row['Database'], $exclude_db)){
        echo $row['Database'] . "<br />\n";
    }
}

Edited:

Also we can exclude in query itself like below.

SELECT `schema_name` from INFORMATION_SCHEMA.SCHEMATA  WHERE `schema_name` NOT IN('information_schema', 'mysql', 'performance_schema');