该curl的等效请求命令

Question

I have a curl command which is working fine and uploading the file to the server.

curl -v <url> --fail --user <username>:<password> --upload-file filename

I have tried the requests module in python. The command I am issuing is

fileobj = open('dist\\test.zip', 'rb')
requests.put(__url, data={"upload": "upload"}, files={"archive": ("test.zip", fileobj)}, auth=HTTPBasicAuth(username,password))

the python request is not working and returning Bad Request , error 400 .

What can be the equivalent python command ?

Answer 1

I was able to figure out the solution to my problem.

zip_file = open(os.path.join(root, file), 'rb')
headers = {'content-type': 'application/zip'}
return_val = requests.put(url=url, data=zip_file, auth=HTTPBasicAuth(username, password),headers=header_type)