匹配字符串中除引号外的所有内容

Question

I am trying to match anything except between ' quotes '. If possible between ' " ` quotes (I know I can use ['"`] ).

Here is my regex pattern which just gets all text in between ' " ` .

^((?!\'.*\').*)$

Regex101 link

Note: I am talking about JavaScript Regex, therefor, I don't need PHP or Python regex patterns.

 let string = 'lorem \\'ipsum\\' dolor' let match = string.match(/^((?!\\'.*\\').*)$/) console.log('[===Real output===]') console.log(match[1]) console.log('[===Expected output===]') console.log('lorem dolor') 

Answer 1

Match the " ' ** and then use that match to find the other one, after matching any characters besides the one of the **" ' that we just found

string.replace(/(['"`])(?:(?!\1)[\s\S])+\1/g, '')

If you want it to match no characters in between marks, as well, then:

string.replace(/(['"`]).*?\1/g, '')

Answer 2

To separate the quotes by type so they do not get mixed (ex. "words' ), \\B : Non-word Boundary meta sequence was wrapped around each QUOTE .+? QUOTE and then each of those expressions separated by | : OR.

/(\B(".+?")\B|\B('.+?')\B|\B(`.+?`)\B)/g;

Alternatively, QUOTE .*? QUOTE could be used if you expect empty quotes as well.

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RegEx101

Demo

 var rgx = /(\\B(".+?")\\B|\\B('.+?')\\B|\\B(`.+?`)\\B)/g; var str = `"Lorem ipsum dolor sit amet", consectetur adipisicing elit, "'sed do eiusmod tempor,'" incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, \\`quis nostrud\\` exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. \\`Duis aute irure dolor\\` in "reprehenderit in voluptate" velit esse cillum 'dolore eu fugiat nulla' pariatur. `; var sub = ``; var res = str.replace(rgx, sub); console.log(res);