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尝试在熊猫中删除列时出现keyError。

[英]keyError when trying to drop a column in pandas.

I want to drop some rows from the data. 我想从数据中删除一些行。 I am using following code- 我正在使用以下代码-

    import pandas as pd
    import numpy as np

    vle = pd.read_csv('/home/user/Documents/MOOC dataset original/vle.csv')


    df = pd.DataFrame(vle)
    df.dropna(subset = ['week_from'],axis=1,inplace = True)
    df.dropna(subset = ['week_to'],axis=1,inplace = True)
    df.to_csv('/home/user/Documents/MOOC dataset cleaned/studentRegistration.csv')

but its throwing following error- 但它引发以下错误-

      raise KeyError(list(np.compress(check,subset)))
      KeyError: [' week_from ']      

what is going wrong? 怎么了?

I think need omit axis=1 , because default value is axis=0 for remove rows with NaNs (missing values) by dropna by subset of columns for check NaN s, also solution should be simplify to one line: 我认为需要省略axis=1 ,因为默认值是axis=0用于通过dropna按检查NaNdropna集删除具有NaNs(缺失值)的行,所以解决方案也应简化为一行:

df.dropna(subset = ['week_from', 'week_to'], inplace = True)

Sample : 样品

df = pd.DataFrame({'A':list('abcdef'),
                   'week_from':[np.nan,5,4,5,5,4],
                   'week_to':[1,3,np.nan,7,1,0],
                   'E':[5,3,6,9,2,np.nan],
                   'F':list('aaabbb')})

print (df)
   A  week_from  week_to    E  F
0  a        NaN      1.0  5.0  a
1  b        5.0      3.0  3.0  a
2  c        4.0      NaN  6.0  a
3  d        5.0      7.0  9.0  b
4  e        5.0      1.0  2.0  b
5  f        4.0      0.0  NaN  b

df.dropna(subset = ['week_from', 'week_to'], inplace = True)
print (df)
   A  week_from  week_to    E  F
1  b        5.0      3.0  3.0  a
3  d        5.0      7.0  9.0  b
4  e        5.0      1.0  2.0  b
5  f        4.0      0.0  NaN  b

If want remove columns by specifying rows for check NaN s: 如果要通过为check NaN指定行来删除列:

df.dropna(subset = [2, 5], axis=1, inplace = True)
print (df)
   A  week_from  F
0  a        NaN  a
1  b        5.0  a
2  c        4.0  a
3  d        5.0  b
4  e        5.0  b
5  f        4.0  b

But if need remove columns by names solution is different, need drop : 但是如果需要按名称删除列的解决方案不同,则需要drop

df.drop(['A','week_from'],axis=1, inplace = True)
print (df)
   week_to    E  F
0      1.0  5.0  a
1      3.0  3.0  a
2      NaN  6.0  a
3      7.0  9.0  b
4      1.0  2.0  b
5      0.0  NaN  b

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