RegExp替换所有字母，但不替换首尾

Question

I have to replace all letters of name on ****. Example:

Jeniffer -> J****r

I try $(this).text( $(this).text().replace(/([^\\w])\\//g, "*"))

Also, if name is Ron -> R****n

Answer 1

You can use a regular expression for this, by capturing the first and last letters in a capture group and ignoring all letters between them, then using the capture groups in the replacement:

var updated = name.replace(/^(.).*(.)$/, "$1****$2");

Live Example:

 function obscure(name) { return name.replace(/^(.).*(.)$/, "$1****$2"); } function test(name) { console.log(name, "=>", obscure(name)); } test("Ron"); test("Jeniffer"); 

But it's perhaps easier without:

var updated = name[0] + "****" + name[name.length - 1];

Live Example:

 function obscure(name) { return name[0] + "****" + name[name.length - 1];; } function test(name) { console.log(name, "=>", obscure(name)); } test("Ron"); test("Jeniffer"); 

Both of those do assume the names will be at least two characters long. I pity the fool who tries this on Mr. T's surname.

Answer 2

Since, you need to have four asterisk on each condition, you can create a reusable function that will create this format for you:

 function replace(str){ var firstChar = str.charAt(0); var lastChar = str.charAt(str.length-1); return firstChar + '****' + lastChar; } var str = 'Jeniffer'; console.log(replace(str)); str = 'America'; console.log(replace(str)) 

Answer 3

Appears that you're looking for regex lookaround

Regex: (?<=\\w)(\\w+)(?=\\w) - group 1 matches all characters which follow one character and followed by another one.

Tests: https://regex101.com/r/PPeEqx/2/

More Info: https://www.regular-expressions.info/lookaround.html

Answer 4

Find first and last chars and append **** to the first one and add the last one:

const firstName = 'Jeniffer';

const result = firstName.match(/^.|.$/gi).reduce((s, c, i) => `${s}${!i ? `${c}****` : c }`, '');

console.log(result);