Python：从DataFrame中的两列创建结构化的numpy结构化数组

Question

How do you create a structured array from two columns in a DataFrame? I tried this:

df = pd.DataFrame(data=[[1,2],[10,20]], columns=['a','b'])
df

    a   b
0   1   2
1   10  20

x = np.array([([val for val in list(df['a'])],
               [val for val in list(df['b'])])])

But this gives me this:

array([[[ 1, 10],
        [ 2, 20]]])

But I wanted this:

[(1,2),(10,20)]

Thanks!

Answer 1

There are a couple of methods. You may experience a loss in performance and functionality relative to regular NumPy arrays.

record array

You can use pd.DataFrame.to_records with index=False . Technically, this is a record array , but for many purposes this will be sufficient.

res1 = df.to_records(index=False)

print(res1)

rec.array([(1, 2), (10, 20)], 
          dtype=[('a', '<i8'), ('b', '<i8')])

structured array

Manually, you can construct a structured array via conversion to tuple by row, then specifying a list of tuples for the dtype parameter.

s = df.dtypes
res2 = np.array([tuple(x) for x in df.values], dtype=list(zip(s.index, s)))

print(res2)

array([(1, 2), (10, 20)], 
      dtype=[('a', '<i8'), ('b', '<i8')])

What's the difference?

Very little. recarray is a subclass of ndarray , the regular NumPy array type. On the other hand, the structured array in the second example is of type ndarray .

type(res1)                    # numpy.recarray
isinstance(res1, np.ndarray)  # True
type(res2)                    # numpy.ndarray

The main difference is record arrays facilitate attribute lookup, while structured arrays will yield AttributeError :

print(res1.a)
array([ 1, 10], dtype=int64)

print(res2.a)
AttributeError: 'numpy.ndarray' object has no attribute 'a'

Related: NumPy “record array” or “structured array” or “recarray”

Answer 2

Use list comprehension for convert nested list s to tuple s:

print ([tuple(x) for x in df.values.tolist()])
[(1, 2), (10, 20)]

Detail :

print (df.values.tolist())
[[1, 2], [10, 20]]

EDIT: You can convert by to_records and then to np.asarray , check link :

df = pd.DataFrame(data=[[True, 1,2],[False, 10,20]], columns=['a','b','c'])
print (df)
       a   b   c
0   True   1   2
1  False  10  20

print (np.asarray(df.to_records(index=False)))
[( True,  1,  2) (False, 10, 20)]

Answer 3

Here's a one-liner:

list(df.apply(lambda x: tuple(x), axis=1))

or

df.apply(lambda x: tuple(x), axis=1).values