[英]Codeigniter $query->row_array() SQL $query->result_array()
So I am trying to get a single item data like itemID, itemSKU etc. from multiple tables. 所以我试图从多个表中获取单个项目数据,例如itemID,itemSKU等。 And display in the view.
并在视图中显示。 The example item I provided down below has three images attached.If I use return $query->row_array();
我在下面提供的示例项带有三个图像。如果使用return $ query-> row_array(); I will get only one row returned.
我只会返回一行。 If I use $query->result_array(), I will get three rows returned.
如果我使用$ query-> result_array(),我将返回三行。 For single item page, I don't want to use foreach to display the result.
对于单个项目页面,我不想使用foreach来显示结果。
My Model 我的模特
$this->db->join('itemsToCats', 'items.itemID = itemsToCats.itemId','left');
$this->db->join('categories', 'itemsToCats.catId = categories.ctgID', 'left');
$this->db->join('itemImg', ' items.itemID = itemImg.itemID', 'left');
$this->db->select('items.itemID, itemSKU, itemName, itemSDesc, addDate, chgDate, ctgID, ctgName, parentID, itemImg');
$query = $this->db->get_where('items', array('items.itemID' => $itemID));
return $query->row_array();
Output 产量
Array
(
[itemID] => 521
[itemSKU] => image part number
[itemName] => multiple images
[itemSDesc] =>
[addDate] => 2018-07-12 16:17:09
[chgDate] => 0000-00-00 00:00:00
[ctgID] => 67
[ctgName] => Pipe Bending
[parentID] => 46
[itemImg] => 234-gy_hello1.png
)
If I use return $query->result_array() I get this: 如果我使用return $ query-> result_array(),则会得到以下信息:
Array
(
[0] => Array
(
[itemID] => 521
[itemSKU] => image part number
[itemName] => multiple images
[itemSDesc] =>
[addDate] => 2018-07-12 16:17:09
[chgDate] => 0000-00-00 00:00:00
[ctgID] => 67
[ctgName] => Pipe Bending
[parentID] => 46
[itemImg] => 234-gy_hello1.png
)
[1] => Array
(
[itemID] => 521
[itemSKU] => image part number
[itemName] => multiple images
[itemSDesc] =>
[addDate] => 2018-07-12 16:17:09
[chgDate] => 0000-00-00 00:00:00
[ctgID] => 67
[ctgName] => Pipe Bending
[parentID] => 46
[itemImg] => cac1f0ad0720ac05e76fd990de2d309e.png
)
[2] => Array
(
[itemID] => 521
[itemSKU] => image part number
[itemName] => multiple images
[itemSDesc] =>
[addDate] => 2018-07-12 16:17:09
[chgDate] => 0000-00-00 00:00:00
[ctgID] => 67
[ctgName] => Pipe Bending
[parentID] => 46
[itemImg] => eee779a15e340e2a0f4d0b682e900862.png
)
)
What I want is this: 我想要的是:
Array
(
[itemID] => 521
[itemSKU] => image part number
[itemName] => multiple images
[itemSDesc] =>
[addDate] => 2018-07-12 16:17:09
[chgDate] => 0000-00-00 00:00:00
[ctgID] => 67
[ctgName] => Pipe Bending
[parentID] => 46
[itemImg] => Array
(
[0] => 234-gy_hello1.png
[1] => cac1f0ad0720ac05e76fd990de2d309e.png
[2] => eee779a15e340e2a0f4d0b682e900862.png
)
)
Is there some SQL trick I can use to achieve the data structure, or I need to modify the result data in the model? 我可以使用一些SQL技巧来实现数据结构,还是需要在模型中修改结果数据? Thank you!
谢谢!
Hope this will help you : 希望这个能对您有所帮助 :
You can modify your result array like this : 您可以像这样修改结果数组:
$this->db->join('itemsToCats', 'items.itemID = itemsToCats.itemId','left');
$this->db->join('categories', 'itemsToCats.catId = categories.ctgID', 'left');
$this->db->join('itemImg', ' items.itemID = itemImg.itemID', 'left');
$this->db->select('items.itemID, itemSKU, itemName, itemSDesc, addDate, chgDate, ctgID, ctgName, parentID, itemImg');
$query = $this->db->get_where('items', array('items.itemID' => $itemID));
if ($query->num_rows() > 0 )
{
foreach ($query->result_array() as $key => $item)
{
$data['itemID'] = $item['itemID'];
$data['itemSKU'] = $item['itemSKU'];
$data['itemName'] = $item['itemName'];
$data['itemSDesc'] = $item['itemSDesc'];
$data['addDate'] = $item['addDate'];
$data['chgDate'] = $item['chgDate'];
$data['ctgID'] = $item['ctgID'];
$data['ctgName'] = $item['ctgName'];
$data['parentID'] = $item['parentID'];
$data['itemImg'][$key] = $item['itemImg'];
}
}
//print_r($data);die;
return $data;
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