从Python列表中删除单词

Question

I have a list 'abc' (strings) and I am trying to remove some words present in list 'stop' from the list 'abc' and all the digits present in abc.

abc=[ 'issues in performance 421',
 'how are you doing',
 'hey my name is abc, 143 what is your name',
 'attention pleased',
 'compliance installed 234']
stop=['attention', 'installed']

I am using list comprehension to remove it but this below code is not able to remove that word.

new_word=[word for word in abc if word not in stop ]

Result:(attention word is still present.)

['issues in performance',
 'how are you doing',
 'hey my name is abc, what is your name',
 'attention pleased',
 'compliance installed']

Desired output:

 ['issues in performance',
     'how are you doing',
     'hey my name is abc, what is your name',
     'pleased',
     'compliance']

Thanks

Answer 1

You need to split each phrase into words and re-join the words into phrases after filtering out those in stop .

[' '.join(w for w in p.split() if w not in stop) for p in abc]

This outputs:

['issues in performance', 'how are you doing', 'hey my name is abc, what is your name', 'pleased', 'compliance installed']

Answer 2

It's just need to use set will good to this question. Because you maybe have more than one word at each item, so you can't use in . you should use set with & to get the public word. If it's exists public word with your stop set will return True . Because you only care about the rest part , so we can use if not here.

new_word=[word for word in abc if  not set(word.split(' ')) & set(stop)]

UPDATE

If you also want to delete all include digit item, you just simple do it with the following :

new_word=[word for word in abc if  not (set(word.split(' ')) & set(stop) or any([i.strip().isdigit() for i in word.split(' ')]))]

Answer 3

Here is a solution, using simple regular expression with the re.sub method. This solution removes numbers as well.

import re

abc=[ 'issues in performance 421',
 'how are you doing',
 'hey my name is abc, 143 what is your name',
 'attention pleased',
 'compliance installed 234']
stop=['attention\s+', 'installed\s+', '[0-9]']

[(lambda x: re.sub(r'|'.join(stop), '', x))(x) for x in abc]


'Output':
['issues in performance ',
'how are you doing',
 'hey my name is abc,  what is your name',
 'pleased',
 'compliance ']

Answer 4

list1 = []
for word in abc:
    word1 = ''
    for remove_word in stop:
        word1 = remove_word
        word1 = word.replace(word1, '')
    list1.append(word1)

Answer 5

This is how I'd do it at least:

abc=[ 'issues in performance 421',
    'how are you doing',
    'hey my name is abc, 143 what is your name',
    'attention pleased',
    'compliance installed 234'
]
stop=['attention', 'installed']
for x, elem in enumerate(abc):
    abc[x] = " ".join(filter(lambda x: x not in stop and not x.isdigit(), elem.split()))
print(abc)

result:

['issues in performance',
    'how are you doing',
    'hey my name is abc, what is your name',
    'pleased',
    'compliance']

Hope it helps in any way :)