使用JavaScript对以逗号分隔的字符串数组进行排序

Question

I came across with a weird requirement and I am struggling for last few hours to complete it. Below is my Array of string(just an example, the actual array contains around 2500 records):

var testArray = [
  "130,839.9,855,837.3,848.65,3980489", 
  "129,875,875,828.1,833.25,6926078", 
  "138,891.3,893.3,865.2,868.75,5035618"
]

We have 3 element here of which each element is comma separated(each element have 6 item). ie:

testArray[0] = "130,839.9,855,837.3,848.65,3980489"

My problem is, I wanted to sort testArray based on the first item of each element and convert it to array of array having all value into float, so the output would be:

[
  [129, 875, 875, 828.1, 833.25, 6926078],
  [130, 839.9, 855, 837.3, 848.65, 3980489],
  [138, 891.3, 893.3, 865.2, 868.75, 5035618]
]

I am able to sort individual item but not the entire array as a whole, and I have tried using split and then sort with no luck.

Can someone help me out with this and please let me know if I am not clear.

Answer 1

Convert the array using Array#map within an Array#map , then use Array#sort on the converted array according to the [0] indices ( a[0] - b[0] ):

In ES5

 var testArray = [ "130,839.9,855,837.3,848.65,3980489", "129,875,875,828.1,833.25,6926078", "138,891.3,893.3,865.2,868.75,5035618" ] var converted = testArray.map(function (item) { return item.split(',').map(function (num) { return parseFloat(num); }); }) console.log(converted) var sorted = converted.sort(function (a, b) { return a[0] - b[0] }) console.log(sorted) 

In ES6

 const testArray = [ "130,839.9,855,837.3,848.65,3980489", "129,875,875,828.1,833.25,6926078", "138,891.3,893.3,865.2,868.75,5035618" ] const converted = testArray.map( item => item.split(',').map( num => parseFloat(num) ) ) console.log(converted) const sorted = converted.sort((a, b) => a[0] - b[0]) console.log(sorted) 

In ES6 (condensed)

 const testArray = [ "130,839.9,855,837.3,848.65,3980489", "129,875,875,828.1,833.25,6926078", "138,891.3,893.3,865.2,868.75,5035618" ] const convertedAndSorted = testArray .map(n => n.split(',') .map(num => parseFloat(num))) .sort((a, b) => a[0] - b[0]) console.log(convertedAndSorted) 

Answer 2

First convert each of the Strings to an array of floats values using Array.map() and parseFloat() . After that you can simply sort the array of arrays using Arrays.sort()

Try the following :

 var arr = ["130,839.9,855,837.3,848.65,3980489","129,875,875,828.1,833.25,6926078","138,891.3,893.3,865.2,868.75,5035618"]; var result = arr.map((a)=> a.split(",").map((b)=>parseFloat(b))).sort((a,b)=> a[0] -b[0]); console.log(result); 

Answer 3

Just map the splitted and to number formatted values and sort by the first item.

 var data = ["130,839.9,855,837.3,848.65,3980489", "129,875,875,828.1,833.25,6926078", "138,891.3,893.3,865.2,868.75,5035618"], result = data .map(s => s.split(',').map(Number)) .sort((a, b) => a[0] - b[0]); console.log(result); 

 .as-console-wrapper { max-height: 100% !important; top: 0; } 

Answer 4

var testArray = ["130,839.9,855,837.3,848.65,3980489","129,875,875,828.1,833.25,6926078","138,891.3,893.3,865.2,868.75,5035618"];

const output = [];
for (let i = 0; i < testArray.length; i++) {
    var numbers = testArray[i].split(',');
    for (let j = 0; j < numbers.length; j++) {
        numbers[j] = +numbers[j];
    }
    output[i] = numbers;
}
output.sort(function(x, y) {
    return x[0] - y[0];
});

or shorter

output = testArray.map(s => s.split(',')).map(e => e.map(n => +n)).sort((x, y) => x[0] - y[0]);