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golang从指针类型切片复制指针值

[英]golang copy pointer value from pointer type slice

type Order struct {
    *Res
    Status int
}

type Res struct {
    ResID            int64
    OtaBookID        string
    StayDetail       []*ResElement
    TotalCharge      float64
    CustFName        string
    CustLName        string
    CreateTime       time.Time
}

type ResElement struct {
    Res        *Res
    OtaEleID   string
    OtaRoomID  string
    RoomID     int
    Arrival    time.Time
    Depart     time.Time
    Charge     float64
    CreateTime time.Time
}

I have a slice named orderList to record orders. 我有一个名为orderList的切片来记录订单。 Now i have the first order which OtaBookID is "A123", and i want to copy this order and change its OtaBookID to "B123". 现在,我具有OtaBookID为“ A123”的第一笔订单,并且我想复制此订单并将其OtaBookID更改为“ B123”。 The ResElement type have some other detail info to record this order and i hide them because it not affect my question. ResElement类型还有其他一些详细信息来记录此顺序,我将它们隐藏了,因为它不影响我的问题。 I can success change Res.OtaBookID but i have no idea how to change Res.StayDetail[0].Res.OtaBookID 我可以成功更改Res.OtaBookID,但是我不知道如何更改Res.StayDetail [0] .Res.OtaBookID

func main() {
    var orderList []*Order

    res := new(Res)
    res.OtaBookID = "A123"

    resElt := new(ResElement)
    resElt.Res = res
    res.StayDetail = append(res.StayDetail, resElt)

    order := new(Order)
    order.Res = res

    orderList = append(orderList, order)

    originalOrder := new(Order)
    originalOrder.Res = new(Res)
    *originalOrder.Res = *order.Res
    //originalOrder.Res.StayDetail[0].Res.OtaBookID = "B123" //this will make all become "B123"

    originalOrder.Res.OtaBookID = "B123"

    orderList = append(orderList, originalOrder)

    fmt.Println(orderList[0].Res.OtaBookID)  //A123
    fmt.Println(orderList[1].Res.OtaBookID)  //B123
    fmt.Println(orderList[0].Res.StayDetail[0].Res.OtaBookID)  //A123
    fmt.Println(orderList[1].Res.StayDetail[0].Res.OtaBookID)  //A123, i want this become B123
}

The result i want is orderList[0].Res.OtaBookID and orderList[0].Res.StayDetail[0].Res.OtaBookID is "A123" and other is "B123" 我想要的结果是orderList [0] .Res.OtaBookID和orderList [0] .Res.StayDetail [0] .Res.OtaBookID是“ A123”,其他是“ B123”

ps: Because i'm taking over other's works. ps:因为我要接管别人的作品。 So the three type already fixed and can not adjust. 因此这三种类型已经固定并且无法调整。 I want to know in this situation whether have any method to arrive my goal 我想知道在这种情况下是否有任何方法可以达到我的目标

From your example and clarification we can focus on main to achieve your goal: 从您的示例和说明中,我们可以专注于主要实现您的目标:

type Order struct {
    *Res
    Status int
}

type Res struct {
    ResID            int64
    OtaBookID        string
    StayDetail       []*ResElement
    TotalCharge      float64
    CustFName        string
    CustLName        string
    CreateTime       time.Time
}

type ResElement struct {
    Res        *Res
    OtaEleID   string
    OtaRoomID  string
    RoomID     int
    Arrival    time.Time
    Depart     time.Time
    Charge     float64
    CreateTime time.Time
}

func main() {
    var orderList []*Order

    res := new(Res)
    res.OtaBookID = "A123"

    resElt := new(ResElement)
    resElt.Res = res
    res.StayDetail = append(res.StayDetail, resElt)

    order := new(Order)
    order.Res = res

    orderList = append(orderList, order)

    originalOrder := new(Order)
    originalOrder.Res = new(Res)

    // The following statement will copy the values in the memory space of order to the memory
    // space of originalOrder, but take note that a pointer contains a memory address. Thus,
    // following this statement originalOrder.Res.StayDetail will point to the same address
    // as order.Res.StayDetail as slices are pointers...
    *originalOrder.Res = *order.Res

    // We now have to manually copy the slice to ensure it is different from the one in order.
    // We must create a new slice to avoid overwriting the source.
    originalOrder.Res.StayDetail := make([]*ResElement, len(order.Res.StayDetail))

    // Further, this slice contains pointers so we must copy these as well to ensure they do not
    // point to the ResElements of order.
    for i, v := range order.Res.StayDetail {
        re := new(ResElement)

        // copy the values of the memory in v to the values in the memory of re
        *re = *v

        // set re.Res to point to originalOrder.Res as it currently point to order.Res
        re.Res = originalOrder.Res

        // Now we must place re in the slice of originalOrder as it currently points to an
        // empty array of the correct size. Thus, we will not use append (which will grow
        // the size), we will just set the index to the correct value. Thus:
        originalOrder.StayDetail[i] = re
    }
    // The pointers and structures have now been properly set up, thus the following are equivalent:
    // originalOrder.OtaBookID = "B123" - Res via embedding
    // originalOrder.Res.OtaBookID = "B123" - Res directly
    // originalOrder.Res.StayDetail[0].Res.OtaBookID = "B123" - Res via ResElement pointer Res
    // They all point to the exact same memory space

    originalOrder.Res.OtaBookID = "B123"

    orderList = append(orderList, originalOrder)

    fmt.Println(orderList[0].Res.OtaBookID)  //A123
    fmt.Println(orderList[1].Res.OtaBookID)  //B123
    fmt.Println(orderList[0].Res.StayDetail[0].Res.OtaBookID)  //A123
    fmt.Println(orderList[1].Res.StayDetail[0].Res.OtaBookID)  //B123
}

Always remember that a pointer is just a memory address. 永远记住,指针只是一个内存地址。 If the address value is 0xffab67e1 a copy of the pointer will also contain the same value of 0xffab67e1 and effectively point to the same thing. 如果地址值为0xffab67e1,则指针的副本也将包含相同的值0xffab67e1,并有效地指向同一对象。 Thus you must deliberately assign new memory space at a new address and copy the internal values. 因此,您必须故意在新地址处分配新的内存空间,并复制内部值。 This must be done for any structures that contain pointers. 必须对任何包含指针的结构执行此操作。 We call this a Deep Copy or a Clone. 我们称其为深拷贝或克隆。

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