[英]Python TypeError: 'bool' object is not iterable
I'm running this code in an attempt to assign key value pairs using a dict. 我正在运行此代码,以尝试使用dict分配键值对。 to store the data (key = xvalue, yvalue) which is in two separate arrays.
存储在两个单独的数组中的数据(键= xvalue,yvalue)。 ie
即
1 def main():
2 path = 'some/path/'
3
4
5 d = {}
6 xcord = [1.2,2.4,2.9,3.0,4.1]
7 ycord = [1.0,2.0,3.0,4.0,5.0]
8 a=0
9 b=0
10 while b < 136 and a <= 21 :
11 for x in xcord and y in ycord :
12 --> d{b}.append(xcord[x],ycord[y])
13 b=b+1
14 if a == 21:
15 a=0
16 else:
17 a=a+1
18 print(d)
19
20 if __name__ == "__main__":
21 main()
But when I run this I get a TypeError: 但是当我运行它时,我得到一个TypeError:
File "some/path/", line 21, in <module>
main()
File "some/path", line 12, in main
for x in xcord and y in ycord :
TypeError: 'bool' object is not iterable
I'm looking to append data from the xcord and ycord arrays to the dictionary and I'm clearly not doing this correctly. 我想将数据从xcord和ycord数组追加到字典中,但是显然我没有正确地做到这一点。
I was thinking I could reference the dict for future calculations like this for example: 我当时想我可以参考字典,以便将来进行如下计算:
print(d{0})
# with a result
{1.2 , 1.0}
# or say I want to calculate slop between two points
sqrt((d{0, [1],[]} - d{2, [1],[]})sqrd + (d{0, [],[1]} - d{2, [], [1]})sqrd)
# with a result
3.2
Please critique me on the Pythonic ways, I am new to Python. 请以Python的方式批评我,我是Python的新手。 and any help is appreciated.
和任何帮助表示赞赏。 I know the math portion is not correct as I was just show some syntax to help explain
我知道数学部分不正确,因为我只是显示一些语法来帮助解释
Replace: 更换:
for x in xcord and y in ycord :
With: 带有:
for x,y in zip(xcord,ycord):
And lot more mistakes, so your code should be like this: 还有更多错误,因此您的代码应如下所示:
def main():
path = 'some/path/'
d = {}
xcord = [1.2,2.4,2.9,3.0,4.1]
ycord = [1.0,2.0,3.0,4.0,5.0]
a=0
b=0
while b < 136 and a <= 21 :
for x,y in zip(xcord,ycord):
if b in d:
d[b].append(x,y)
else:
d[b]=[x,y]
b=b+1
if a == 21:
a=0
else:
a=a+1
print(d)
if __name__ == "__main__":
main()
Thanks to everyone for the support in my early python coding days. 感谢大家在我早期的python编码时代的支持。
The solution I found to work with what exactly I was expecting for the output was: 我发现可以与我期望的输出完全兼容的解决方案是:
d = {}
b = 0
xcord = [1.2,2.4,2.9,3.0,4.1]
ycord = [1.0,2.0,3.0,4.0,5.0]
for x,y in zip(xcord,ycord):
if b in d:
d[b].append(x,y)
else:
d[b] = [x,y]
b=b+1
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