红移COUNT（DISTINCT（））。 计算每个ID的唯一日期

Question

I'm trying to do a distinct count of dates for each ID in my table. I tried this code but it's not returning the correct output.

SELECT *
, DENSE_RANK() OVER(PARTITION BY "video_id" ORDER BY "date") AS "distinct_count_date"
FROM mytable
;   

Answer 1

Perhaps you need :

select video_id, count(distinct date)
from mytable
group by video_id;