如何从字符串中提取列表时间？

Question

I want to extract the list of time from this string

20:00-24:00、17:00-21:00、6:30-9:00 など、夜中心に募集！6:30-24:00の間で 1日2時間～ＯＫ！夏休みの短期も可

Answer 1

You can make use the following regex:

((?:[01]?\d|2[0-3]):[0-5]\d)-((?:[01]?\d|2[0-3]):[0-5]\d)

Which matches on a range. Eg: 15:56-23:10 .

This can then be used in conjunction with the Pattern class from java.util.regex , to find out every range in the input string:

Pattern pattern = Pattern.compile("((?:[01]?\\d|2[0-3]):[0-5]\\d)-((?:[01]?\\d|2[0-3]):[0-5]\\d)");
Matcher matcher = pattern.matcher(input);
while(matcher.find()){
    String from = matcher.group(1);
    String to = matcher.group(2);
}

Answer 2

Regex: ([0-2]?\\d:[0-5]\\d)-([0-2]?\\d:[0-5]\\d)

Online test: Link

Java implementation:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

final String regex = "([0-2]?\\d:[0-5]\\d)-([0-2]?\\d:[0-5]\\d)";
final String string = "20:00-24:00、17:00-21:00、6:30-9:00 など、夜中心に募集！6:30-24:00の間で 1日2時間～ＯＫ！夏休みの短期も可";

final Pattern pattern = Pattern.compile(regex, Pattern.MULTILINE);
final Matcher matcher = pattern.matcher(string);

while (matcher.find()) {
    System.out.println("Full match: " + matcher.group(0));
    for (int i = 1; i <= matcher.groupCount(); i++) {
        System.out.println("Group " + i + ": " + matcher.group(i));
    }
}