[英]Write JSON for corresponding XML
I want to write JSON code which can be converted in fix format kind of XML 我想编写可以以固定格式的XML格式转换的JSON代码
<function>foo
<return>uint32_t</return>
<param>count
<type>uint32_t</type>
</param>
</function>
I have tried multiple ways to develop a JSON which can be formatted like as in above but failed to get perfection because no separate key is required for foo and count which are orphan values otherwise. 我尝试了多种方法来开发可以像上面一样格式化的JSON,但是由于没有必要为foo和count分配单独的键(否则它们是孤立值),因此无法完美实现。
Tried ways: Way 1: 尝试的方式:方法1:
{
"function" :
{"foo":
{"return":"uint32_t"},
"param":
{"count":
{"type":"uint32_t"}
}
}
}
Way 2: 方式2:
{
"function" :
["foo",{"return":"uint32_t"}],
"param":
["count",{"type":"uint32_t"}]
}
Way 3: But i do not need name tag :( 方式3:但是我不需要名称标签:(
{
"function":
{"name": "foo",
"return": "uint32_t",
"param": "count",
"type": "uint32_t"
}
}
For generating output and testing please use: JSON to XML convertor 为了生成输出和测试,请使用: JSON到XML转换器
Requesting your help.. I later have a script to convert the formatted excel to C header files. 请求您的帮助。. 后来我有了一个脚本,可以将格式化的excel转换为C头文件。
It is very rare for a JSON-to-XML conversion library to give you precise control over the XML that is generated, or conversely, for an XML-to-JSON converter to give you precise control over the JSON that is generated. 很少有JSON到XML转换库为您提供对所生成的XML的精确控制,或者相反,对于XML到JSON转换器则为您提供对所生成的JSON的精确控制。 It's basically not possible because the data models are very different.
基本上是不可能的,因为数据模型非常不同。
Typically you have to accept what the JSON-to-XML converter gives you, and then use XSLT to transform it into the flavour of XML that you actually want. 通常,您必须接受JSON-to-XML转换器提供的功能,然后使用XSLT将其转换为您实际想要的XML风格。
(Consider using the json-to-xml() conversion function in XSLT 3.0 and then applying template rules to the result.) (考虑在XSLT 3.0中使用json-to-xml()转换函数,然后将模板规则应用于结果。)
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