[英]How to bootstrap modal popup via a variable?
I am studying the bootstrap, and follow the example: 我正在研究引导程序,并按照示例进行操作:
<button class="btn btn-primary btn-lg" data-toggle="modal" data-target="#myModal">
Shows the modal
</button>
<div class="modal fade" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="false">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">
×
</button>
<h4 class="modal-title" id="myModalLabel">
模态框(Modal)标题
</h4>
</div>
<div class="modal-body">
在这里添加一些文本
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">关闭
</button>
<button type="button" class="btn btn-primary">
提交更改
</button>
</div>
</div><!-- /.modal-content -->
</div><!-- /.modal -->
</div>
if I click the button the modal will popup, but I don't understand which variable is controlling the modal popup and disappear. 如果单击按钮,将弹出模式对话框,但我不知道哪个变量控制着模式弹出窗口并消失。
I want to through a variable to popup it. 我想通过一个变量来弹出它。 there is a requirement. 有一个要求。
when I enter a Smarty page, if the page do not exists a access_token variable, I want the modal popup automatically. 当我进入一个Smarty页面时,如果该页面不存在access_token变量,我希望自动弹出模式对话框。
So, how to realize in this example? 那么,在这个例子中如何实现?
Trigger the show method. 触发show方法。
var myModal = $("#myModal"); myModal.modal("show");
To show a modal: $('#myModal').modal('show'); 显示模态:$('#myModal')。modal('show');
To hide a modal: $('#myModal').modal('hide'); 隐藏模态:$('#myModal')。modal('hide');
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