我在将IF else语句与Javascript中的函数配对时遇到麻烦

Question

function calcPyth() {
    let v1 = document.getElementById("v1").value;
    let v2 = document.getElementById("v2").value;
    let v3 = document.getElementById("v3").value;

    if ((v1 * v1) == (v2*v2)+(v3*v3)) {
        alert("These are pythagoras triplets");
    } else if ((v1 * v1) < (v2*v2) + (v3*v3)) {
        alert("This is an obtuse triangle");
    } else {
        alert("This is an acute triangle");
    }
}

When I try to run to run the statement, it only returns the else if value.I have no idea what to do.

Answer 1

You need to check all possible combination for Pythagoras triplet.

 function calcPyth() { let v1 = parseInt(document.getElementById("v1").value); let v2 = parseInt(document.getElementById("v2").value); let v3 = parseInt(document.getElementById("v3").value); if ((v1 * v1) == (v2*v2)+(v3*v3) || (v2 * v2) == (v1*v1)+(v3*v3) || (v3 * v3) == (v1*v1)+(v2*v2)) { alert("These are pythagoras triplets"); } else if ((v1 * v1) < (v2*v2) + (v3*v3)) { alert("This is an obtuse triangle"); } else { alert("This is an acute triangle"); } } 

 <input type="text" id="v1" value="3"/><br/> <input type="text" id="v2" value="4"/><br/> <input type="text" id="v3" value="5"/><br/> <button onClick="calcPyth()">calcPyth</button>