如何检查按钮是否被禁用？

Question

Hello I have the following code:

async function pressNext(nightmare) {
    const check = await check_nextButton(nightmare);
    const disabled= await check_disabled();
    if(check&&disabled) {
        await nightmare.click('#example_next');
        await extractInfo(nightmare);
        return pressNext(nightmare);
    }
    return null;
}

It is supposed to click the next button on a table as long as it exists , the problem is that the button exists even after it becomes disabled, so I can't think of any way to check if the "next button" is disabled The check disabled function is just something I've tried but didn't work , so I need to somehow make that function be true only if the #example_next is not disabled EDIT: image of Next enabled

image of Next disabled

I tried comparing the classNames and that doesn't work

Answer 1

You can use .disabled :

if(!your_button.disabled){ //if not disabled
    # Do something
} else {
    # Do something
}

Answer 2

So I've fixed it guys , I've made a function that fixes it , verifying if the selector for the disabled class exists , i the folllowing

async function check_disabled(nightmare){
   return nightmare.exists('.paginate_button.next.disabled');

}