使用Python获取一周中两天之间的日期

Question

I m parsing an html document using python and beautifulSoup where I get strings with the following format, ie workingdates = 'Wednesday-Tuesday' .

From that point i get startDate = 'Wednesday' and endDate = 'Tuesday' .

I want to create a list with all the working days ie list=['Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday', 'Monday', 'Tuesday']

Any ideas?

Answer 1

You can construct a list of all week days

weekdays = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 
             'Friday', 'Saturday', 'Sunday']

and having defined your start and end dates

startDate, endDate  = 'Wednesday', 'Tuesday'

you can find their positions in the weekdays list

start = weekdays.index(startDate)
end = weekdays.index(endDate)

there are two possible cases start < end and start > end . For the first case you simply take a normal slice. For the second you slice from start to the end of list and append the part from the beginning of the list up to end .

if start < end:
    lst = weekdays[start: end+1]
else:
    lst = weekdays[start:] + weekdays[:end+1]

Answer 2

You can accomplish this using a list representing a fortnight, by finding the index of the startDate and the index of the first occurrence of the endDate after the startDate :

startDate="Wednesday"
endDate="Tuesday"

week = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
fortnight = week * 2

start = fortnight.index(startDate)
end = fortnight.index(endDate, start + 1) + 1

workingdays = fortnight[start:end]

print(workingdays)
>>> ['Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday', 'Monday', 'Tuesday']

Answer 3

You can also use cycle from itertools :

from itertools import cycle

startDate, endDate = 'Wednesday', 'Tuesday'

l = []
for c in cycle(['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']):
    if not l and c == startDate:
        l.append(c)
    elif l and c == endDate:
        l.append(c)
        break
    elif l:
        l.append(c)

print(l)

Prints:

['Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday', 'Monday', 'Tuesday']