[英]CS50 Credit, loop if not card number
I have nearly finished the Credit task of PSET1 (CS50) although I have run into a problem trying to get the program to not allow an entry that isn't a card number (Eg "Foo" or "t" or anything other than a number) and then loop.我几乎完成了 PSET1 (CS50) 的 Credit 任务,尽管我遇到了一个问题,试图让程序不允许输入不是卡号的条目(例如“Foo”或“t”或除卡号以外的任何内容)号),然后循环。
I have attempted various while statements and goto statements although none of these attempts have been sucessful我尝试了各种 while 语句和 goto 语句,尽管这些尝试都没有成功
Also any other suggestions would be appreciated.任何其他建议也将不胜感激。
#include <stdio.h>
#include <cs50.h>
int main(void)
{
//gets cardnumber & counts digits entered
long long cardnumber;
int count = 0;
{
//prompts user for a cardnumber
printf("Enter a cardnumber: ");
scanf("%lld", &cardnumber);
}
//Prints count of digits entered (will likely not need this part)
//else printf("Number of digits: %d", count); printf("\n");
//Finds first 8 digits for checksum)
int digit1 = (((cardnumber % 100) / 10) * 2);
int digit2 = (((cardnumber % 10000) / 1000) * 2);
int digit3 = (((cardnumber % 1000000) / 100000) * 2);
int digit4 = (((cardnumber % 100000000) / 10000000) * 2);
int digit5 = (((cardnumber % 10000000000) / 1000000000) * 2);
int digit6 = (((cardnumber % 1000000000000) / 100000000000) * 2);
int digit7 = (((cardnumber % 100000000000000) / 10000000000000) * 2);
int digit8 = (((cardnumber % 10000000000000000) / 1000000000000000) * 2);
//Sum first 8 digits of checksum
int check1 = ((digit1 % 10) + (digit1 / 10));
check1 = (check1 + (digit2 % 10)) + (digit2 / 10);
check1 = (check1 + (digit3 % 10)) + (digit3 / 10);
check1 = (check1 + (digit4 % 10)) + (digit4 / 10);
check1 = (check1 + (digit5 % 10)) + (digit5 / 10);
check1 = (check1 + (digit6 % 10)) + (digit6 / 10);
check1 = (check1 + (digit7 % 10)) + (digit7 / 10);
check1 = (check1 + (digit8 % 10)) + (digit8 / 10);
//Sum last 8 digits of checksum & Sum of first 8 (check1)
int digit9 = ((cardnumber % 10) / 1);
int digit10 = ((cardnumber % 1000) / 100);
int digit11 = ((cardnumber % 100000) / 10000);
int digit12 = ((cardnumber % 10000000) / 1000000);
int digit13 = ((cardnumber % 1000000000) / 100000000);
int digit14 = ((cardnumber % 100000000000) / 10000000000);
int digit15 = ((cardnumber % 10000000000000) / 1000000000000);
int digit16 = ((cardnumber % 1000000000000000) / 100000000000000);
//add to remaining digits to those that were multiplied by 2
int checksum = (check1 + digit9 + digit10 + digit11 + digit12 + digit13 + digit14 + digit15 + digit16);
// Check first 2 digits
if (cardnumber / 10000000000000 == 34 || cardnumber / 10000000000000 == 37 )
goto Amex;
if (cardnumber / 100000000000000 == 51 || cardnumber / 100000000000000 == 52 || cardnumber / 100000000000000 == 53 || cardnumber / 100000000000000 == 54 || cardnumber / 100000000000000 == 55 )
goto Master;
if (cardnumber / 1000000000000000 == 4 )
goto Visa;
else
{
printf("INVALID\n");
(I = 0);
}
goto End;
// Amex start with 34 or 37
Amex:;
char A;
if (cardnumber / 10000000000000 == 34 || cardnumber / 10000000000000 == 37 )
{
A = 1;
}
else
{
A = 0;
}
goto End;
// Mastercard start with 51, 52, 53, 54, 55
Master:;
char M;
if (cardnumber / 100000000000000 == 51 || cardnumber / 100000000000000 == 52 || cardnumber / 100000000000000 == 53 || cardnumber / 100000000000000 == 54 || cardnumber / 100000000000000 == 55 )
{
M = 1;
}
else
{
M = 0;
}
goto End;
//Visa start with 4
Visa:;
char V;
if (cardnumber / 1000000000000000 == 4 )
{
V = 1;
}
else
{
V = 0;
}
goto End;
End:;
while(cardnumber != 0)
{
// cardnumber = cardnumber/10
cardnumber /= 10;
++count;
}
// if cardnumber <13 or >16 digits error "invalid card" given
if (count > 16 || count < 13)
{
printf("INVALID\n");
(I = 0);
}
// Keep track of first 2 digits & validate checksum
char T;
if (checksum % 10 == 0)
{
T = 1;
}
else
{
T = 0;
}
if (T == 0) printf("INVALID\n");
{
(I = 0);
}
// - Amex (15 digits, start with 34 or 37)
if (count == 15 && T == 1 && A == 1)
{
printf("AMEX\n");
}
// - Mastercard (16 digits, start with 51, 52, 53, 54, 55)
if (count == 16 && T == 1 && M == 1)
{
printf("MASTERCARD\n");
}
// - Visa (13 & 16 digits, start with 4)
if ((count == 13 && T == 1 && V == 1) || (count == 16 && T == 1 && V == 1))
{
printf("VISA\n");
}
}
Prompt the user to type in the credit card number, use a do while loop so that if the number is less than 0, you will keep asking the user for a card number.提示用户输入信用卡号,使用 do while 循环,这样如果数字小于 0,您将不断向用户询问卡号。
int main(void)
{
long long credit_card_number;
do
{
credit_card_number = get_long_long("Enter Valid Credit Card Number: ");
}
while (credit_card_number < 0);
#include <cs50.h>
#include <math.h>
#include <stdio.h>
int main(void)
{
long long cardnumber = 0;
do
{
cardnumber = get_long("Number: ");
}
while (cardnumber < 0);
int count = 0;
long long digits = cardnumber;
while (digits > 0)
{
digits = digits/10;
count++;
}
if ((count != 13) && (count != 15) && (count != 16))
{
printf("INVALID\n");
}
int number[count];
for (int i = 0; i < count; i++)
{
number[i] = cardnumber % 10;
cardnumber = cardnumber / 10;
}
int originalnumber[count];
for (int i = 1; i < count; i++)
{
originalnumber[i] = number[i];
}
for (int i = 1; i < count; i+=2)
{
number[i] = number[i] * 2;
}
int v = 0;
int temp;
if (count == 13)
{
for (int i = 0; i < count; i++)
{
temp = (number[i] % 10) + (number[i]/10 % 10);
v = v + temp;
}
if (originalnumber[12] == 4 && v % 10 == 0)
{
printf("VISA\n");
}
else
{
printf("INVALID\n");
}
}
if (count == 15)
{
for (int i = 0; i < count; i++)
{
temp = (number[i] % 10) + (number[i]/10 % 10);
v = v + temp;
}
if (originalnumber[14] == 3 && v % 10 == 0 && (originalnumber[13] == 4 || originalnumber[13] == 7))
{
printf("AMEX\n");
}
else
{
printf("INVALID\n");
}
}
if (count == 16)
{
for (int i = 0; i < count; i++)
{
temp = (number[i] % 10) + (number[i]/10 % 10);
v = v + temp;
}
if (originalnumber[15] == 4 && v % 10 == 0)
{
printf("VISA\n");
}
else if (originalnumber[15] == 5 && v % 10 == 0 && (originalnumber[14] == 1 || originalnumber[14] == 2 || originalnumber[14] == 3 || originalnumber[14] == 4 || originalnumber[14] == 5))
{
printf("MASTERCARD\n");
}
else
{
printf("INVALID\n");
}
}
}
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