如何从文件列表中获取完整路径？

Question

I have a csv file looks like this:

foo.html,9,0
bar.html,0,3
otherfile.html,9,1

Every row in this csv file, contains a filename. I need to replace the filename with the fullpath of this filename.

for example, foo.html should be replace with c:\\somefolder\\sub\\sub\\foo.html .

• I know that all the files are somewhere inside c:\\somefolder .

How to do that with Powershell ?

Answer 1

Following your comment that you know how to get the names from the csv and know that the files are in the the folder C:\\somefolder you can try to loop this:

$allItems = Get-ChildItem -Recurse C:\somefolder
$fullname = @()

foreach ($item in $itemsFromCsv)
{
  $fullname += $a | Where-Object {$_.Name -eq $file} | Select-Object -ExpandProperty Fullname
}

This searches you the Fullname (path + Name) and saves it in the array $fullname . You can then add the array to your csv and export it.