T-SQL：四舍五入到最近的 15 分钟间隔

Question

What's the best way to round an HH:MM value to the closest 15 minute interval? I don't track seconds so they don't matter.

00:08:00 becomes 00:15:00 
00:07:00 becomes 00:00:00 
01:59:00 becomes 02:00:00 

Answer 1

I am currently using a dateadd \/ datediff variant with a zero (0) date for this. No Casting required:

select dateadd(minute, datediff(minute,0,GETDATE()) / 15 * 15, 0)

Answer 2

I know this is a old post but wanted to share my answer. This builds on @hbrowser response. Here is what I've come up with. This will round up or down to the nearest 15 minutes.

SELECT DATEADD(MINUTE, ROUND(DATEDIFF(MINUTE, 0, GETDATE()) / 15.0, 0) * 15, 0);

By doing this logic inline, rather than inside a user defined function, over large recordsets you should experience greater performance.

You can change the way rounding occurs by swapping the ROUND function to use FLOOR or CAST expr AS INT to always round down or use CEILING to always round up.

Your individual use case will determine what style of rounding you may need to use.

The following script can be used to observe the differences offered by the different rounding techniques:

NOTE: to simplify the output each result has been casted to TIME(0), this is only done to simplify the output for this particular example.

DECLARE @SequenceStart SmallDateTime = CAST(GETDATE() AS Date); 
DECLARE @SequenceEnd SmallDateTime = DateAdd(HOUR, 2, @SequenceStart); -- Recursive CTEs should always have an upper limit
DECLARE @SequenceIntMins INT = 5; -- increment by 5 to show the difference with rounding
WITH TimeSequence([Time]) as
(
    SELECT @SequenceStart as [Time]
    UNION ALL
    SELECT DateAdd(MINUTE, 5, [Time]) FROM TimeSequence 
    WHERE [Time] <= @SequenceEnd
)
    SELECT [Time] = Cast([Time] as TIME(0))
    , Rounded = CAST(DATEADD(MINUTE, ROUND(DATEDIFF(MINUTE, 0, [Time]) / 15.0, 0) * 15, 0) as TIME(0))
    , Casted = CAST(DATEADD(MINUTE, CAST(DATEDIFF(MINUTE, 0, [Time]) / 15.0 AS INT) * 15, 0) as TIME(0))
    , Floored = CAST(DATEADD(MINUTE, FLOOR(DATEDIFF(MINUTE, 0, [Time]) / 15.0) * 15, 0) as TIME(0))
    , Ceilinged = CAST(DATEADD(MINUTE, CEILING(DATEDIFF(MINUTE, 0, [Time]) / 15.0) * 15, 0) as TIME(0))
FROM TimeSequence OPTION ( MaxRecursion 1000);
-- MaxRecursion may be neccessary if you change the interval or end of the sequence

Time        Rounded     Casted      Floored     Ceilinged
00:00:00    00:00:00    00:00:00    00:00:00    00:00:00
00:05:00    00:00:00    00:00:00    00:00:00    00:15:00
00:10:00    00:15:00    00:00:00    00:00:00    00:15:00
00:15:00    00:15:00    00:15:00    00:15:00    00:15:00
00:20:00    00:15:00    00:15:00    00:15:00    00:30:00
00:25:00    00:30:00    00:15:00    00:15:00    00:30:00
00:30:00    00:30:00    00:30:00    00:30:00    00:30:00
00:35:00    00:30:00    00:30:00    00:30:00    00:45:00
00:40:00    00:45:00    00:30:00    00:30:00    00:45:00
00:45:00    00:45:00    00:45:00    00:45:00    00:45:00
00:50:00    00:45:00    00:45:00    00:45:00    01:00:00
00:55:00    01:00:00    00:45:00    00:45:00    01:00:00
01:00:00    01:00:00    01:00:00    01:00:00    01:00:00
01:05:00    01:00:00    01:00:00    01:00:00    01:15:00

Answer 3

This was answered here How to Round a Time in T-SQL and i think it should work for you to.

CREATE FUNCTION [dbo].[RoundTime] (@Time datetime, @RoundTo float) RETURNS datetime
AS
BEGIN
    DECLARE @RoundedTime smalldatetime, @Multiplier float

    SET @Multiplier = 24.0 / @RoundTo

    SET @RoundedTime= ROUND(CAST(CAST(CONVERT(varchar, @Time, 121) AS datetime) AS float) * @Multiplier, 0) / @Multiplier

    RETURN @RoundedTime
END

-- Usage    
SELECT dbo.RoundTime('13:15', 0.5)

Answer 4

You can round a date to the nearest quarter like:

cast(floor(cast(getdate() as float(53))*24*4)/(24*4) as datetime)

Casting datetime to double precesion to avoid overflows, double = float(53). Multiply by 24*4, the number of quarters in a day. Round to the nearest multiple of quarters with floor(), and then divide by 24*4 to convert back to normal time.

Answer 5

Tried Andomar's answer and there was rounding issues at 30 and 00 - so a few tweaks and this works perfectly:

cast(round(floor(cast(getdate() as float(53))*24*4)/(24*4),5) as smalldatetime)

Answer 6

Okay easiest way:

convert the minutes to a decimal number by dividing by 60.

8/60 = 0.1333333333333333

multiply by 4

0.1333333333333333 * 4   = 0.5333333333333333

Round the product:

Round(0.5333333333333333,0) = 1

divide the round number by 4

1/4 = 0.25 = 15 minutes

if you want the minutes just multiply it by 60

0.25*60 = 15

Give a man a fish....

Answer 7

DECLARE @t time  ='00:51:00.000' 
DECLARE @m  int = DATEPART(MI,@t)%15

-- 2008
SELECT DATEADD(mi,CASE WHEN @m >=8 THEN 15-@m ELSE -1*@m END,@t)

-- 2012
SELECT DATEADD(mi,IIF(@m >=8,15-@m,-1*@m),@t)

Answer 8

Try this:

Declare @Dt DateTime 
Set @Dt = getDate()

Select DateAdd(minute, 
        15 * ((60 * Datepart(hour, @Dt) + 
        Datepart(Minute, @Dt)+ 
        Case When DatePart(second, @Dt) < 30 
        Then 7 Else 8 End) / 15),
    DateAdd(day, DateDiff(day, 0, @Dt), 0))

Answer 9

--This is my favorite way to round time

DECLARE @Time DATETIME = GETDATE()
       ,@RoundInterval INT = 30  --in minutes, needs to be a number that can be divided evenly into 60
       ,@RoundDirection INT = 2  --0 is down to the last interval, 1 is to the nearest interval, 2 is up to the next interval

SELECT  DATEADD(MINUTE,DATEDIFF(MINUTE,0,DATEADD(SECOND,30*@RoundDirection*@RoundInterval,@Time))/@RoundInterval*@RoundInterval,0)

Answer 10

how about this one? (variable added for readability)

create function dbo.FloorTimeToQuarters
(
 @dt as datetime
)
RETURNS datetime
as

BEGIN

 DECLARE @timeAsInt bigint
 SET @timeAsInt = ( cast( @dt as float ) * 96 )
 RETURN DateAdd( hour, @timeAsInt % 96, cast( @timeAsInt / 96 as datetime)  )

END

Answer 11

This will round to the nearest 15 minutes. You can modify @ROUND to the interval of your choice.

Declare @Dt DateTime = '2016-01-01 14:38:00' 
DECLARE @ROUND int = 15;
SELECT
CASE WHEN (DATEPART(MINUTE, @Dt) % @ROUND) * 60 + DATEPART(SECOND, @Dt) < (30 * @ROUND)
THEN DATEADD(minute, datediff(minute,0, @Dt) / @ROUND * @ROUND, 0) 
ELSE DATEADD(minute, (DATEDIFF(minute,0, @Dt) / @ROUND * @ROUND) + @ROUND, 0) 
END

Answer 12

Premise breaks down to figuring out what increment you want, what's that as a percent of 60 minutes...then figure out the needed number of increments to get there...take the INT value (this chops off remainders) and there you have it, a simple function to round Up or down to the closest increment.

    ALTER FUNCTION [dbo].[RoundOffDateTime]
(
    @IncDate    DATETIME,
    @Increment  INT
)
RETURNS SMALLDATETIME
AS
BEGIN

    DECLARE @IncrementPercent DECIMAL(2,2) = CAST(@Increment as decimal)/60
    DECLARE @IncMinutes REAL = ROUND(CAST(DATEPART(mi,@IncDate) as decimal)/CAST(@Increment as decimal),0)
    DECLARE @MinutesNeeded INT = CAST(@IncMinutes * @Increment as INT)

    RETURN CAST(DATEADD(mi,@MinutesNeeded,DATEADD(ss,-DATEPART(ss,@IncDate),DATEADD(mi,-DATEPART(mi,@IncDate),@IncDate))) as smalldatetime)

END

Answer 13

    DECLARE   @Date             DATETIME = GETDATE()

    SELECT    @Date
            , DATEADD(ms, 900000 - DATEDIFF(ms, CAST(@Date AS DATE), @Date) % 900000, @Date)

Answer 14

To set block in 15 minutes:

CREATE FUNCTION RoundQuarterHour (
    @dt DATETIME
) RETURNS DATETIME

AS
BEGIN
    DECLARE @date DATETIME
    SET @date = CONVERT(varchar(16),@dt,121) --Sin segundos, ni milisegundos
    RETURN DATEADD(MINUTE,(DATEPART(MINUTE,@date) % 15)*-1, @date)
END

PRINT dbo.RoundQuarterHour('2011/01/01 18:00:07')  --Jan  1 2011  6:00PM
PRINT dbo.RoundQuarterHour('2011/01/01 18:01:07')  --Jan  1 2011  6:00PM
PRINT dbo.RoundQuarterHour('2011/01/01 18:13:07')  --Jan  1 2011  6:00PM
PRINT dbo.RoundQuarterHour('2011/01/01 18:14:07')  --Jan  1 2011  6:00PM
PRINT dbo.RoundQuarterHour('2011/01/01 18:15:07')  --Jan  1 2011  6:15PM
PRINT dbo.RoundQuarterHour('2011/01/01 18:16:07')  --Jan  1 2011  6:15PM

Answer 15

create function RoundQuarterHour
(
    @dt datetime
)
returns datetime
as
begin
    declare @result datetime
    declare @mm int
    set @mm=datepart(minute,@dt)
    set @result = dateadd(minute,-@mm + (round(@mm/cast(15 as float),0)*15) , @dt )

    return @result
end
go


           select dbo.RoundQuarterHour('2009-may-5 20:00') , '00'
 union all select dbo.RoundQuarterHour('2009-may-5 20:01') , '01'
 union all select dbo.RoundQuarterHour('2009-may-5 20:07') , '07'
 union all select dbo.RoundQuarterHour('2009-may-5 20:08') , '08'
 union all select dbo.RoundQuarterHour('2009-may-5 20:22') , '22'
 union all select dbo.RoundQuarterHour('2009-may-5 20:23') , '23'
 union all select dbo.RoundQuarterHour('2009-may-5 20:37') , '37'
 union all select dbo.RoundQuarterHour('2009-may-5 20:38') , '38'
 union all select dbo.RoundQuarterHour('2009-may-5 20:52') , '52'
 union all select dbo.RoundQuarterHour('2009-may-5 20:53') , '53'
 union all select dbo.RoundQuarterHour('2009-may-5 20:59') , '59'

Answer 16

Time rounding in T-SQL is actually very problematic and many times inaccurate.

Years ago, I moved all rounding of times into code vs. using all the extra hub-bub one has to do in T-SQL to make it happen and to happen accurately. Rounding times in code is easier and much more accurate.

If you're stuck in T-SQL and have no supporting code, or don't have access to that code, then follow the examples previously mentioned. Otherwise, I humbly recommend letting code do the work.