[英]Python 3: Using subprocess to take photo via gphoto2 but can't set custom filename doing it.
everything works fine while I do it via terminal but when I use python script it doesn't. 当我通过终端进行操作时,一切正常,但是当我使用python脚本时,一切都没有。
Command: gphoto2 --capture-image-and-download --filename test2.jpg
命令: gphoto2 --capture-image-and-download --filename test2.jpg
New file is in location /capt0000.jpg on the camera
Saving file as test2.jpg
Deleting file /capt0000.jpg on the camera
I'ts all good. 都很好。 But when I try to do it via python script and subprocess nothing happens. 但是,当我尝试通过python脚本和子进程来执行此操作时,没有任何反应。 I tried to do it like: 我试图这样做:
import subprocess
text1 = '--capture-image-and-download"'
text2 = '--filename "test2.jpg"'
print(text1 +" "+ text2)
test = subprocess.Popen(["gphoto2", text1, text2], stdout=subprocess.PIPE)
output = test.communicate()[0]
print(output)
and: 和:
import subprocess
test = subprocess.Popen(["gphoto2", "--capture-image-and-download --filename'test2.jpg'"], stdout=subprocess.PIPE)
output = test.communicate()[0]
print(output)
While I use only --capture-image-and-download
it works fine, but I get filename that I don't want to. 虽然我仅使用--capture-image-and-download
它可以正常工作,但是却得到了我不想使用的文件名。 Can you tell me what I do wrong?! 你能告诉我我做错了吗?
On the command line, quotes and spaces are consumed by the shell; 在命令行上,引号和空格由外壳使用; with shell=False
you need to split up the tokens on whitespace yourself (and ideally understand how the shell processes quotes; or use shlex
to do the work for you). 如果shell=False
,则需要自己在shlex
分割标记(并且最好了解shell如何处理引号;或使用shlex
为您完成工作)。
import subprocess
test = subprocess.Popen([
"gphoto2",
"--capture-image-and-download",
"--filename", "test2.jpg"],
stdout=subprocess.PIPE)
output = test.communicate()[0]
print(output)
Unless you are stuck on a truly paleolithic Python version, you should avoid supbrocess.Popen()
in favor of subprocess.run()
(or, for slightly older Python versions, subprocess.check_output()
). 除非您坚持使用真正的supbrocess.Popen()
Python版本,否则应避免使用supbrocess.Popen()
,而supbrocess.Popen()
subprocess.run()
(或者对于稍旧的Python版本,则使用subprocess.check_output()
)。 The lower-level Popen()
interface is unwieldy, but gives you low-level access control for when the higher-level API doesn't do what you want. 较低级别的Popen()
接口比较笨拙,但是当较高级别的API无法满足您的要求时,它会为您提供低级别的访问控制。
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