[英]How to exclude weekends between two date ranges
I have a FromDate and ToDate and days interval between them. 我有一个FromDate和ToDate以及它们之间的天数间隔。 Now i want to get all date excluding weekends
现在我想获得除周末以外的所有日期
If there is any weekends between my FromDate and ToDate,then this date will be increment by 2 days saturday and sunday. 如果我的FromDate和ToDate之间有任何周末,那么该日期将在周六和周日增加2天。
In below example, i have calculated all date between 7/27/2018 and 8/27/2018 with 5 days interval between them, 在下面的示例中,我计算了7/27/2018至8/27/2018之间的所有日期,它们之间有5天的间隔,
public function testdate(){
$date_from = new \DateTime("7/27/2018");
$date_to = new \DateTime("8/27/2018");
$interval = new \DateInterval("P5D");
$dates = new \DatePeriod($date_from, $interval, $date_to);
$out = array();
if (!empty($dates)) {
foreach($dates as $dt) {
$out[] = array(
'month_year' => $dt->format('d/m/Y')
);
}
}
'<pre>';
//$out = array_reverse($out);
echo print_r($out);
'</pre>';
exit;
}
Expected output 预期产量
Array
(
[0] => Array
(
[month_year] => 27/07/2018
)
[1] => Array
(
[month_year] => 02/08/2018
)
[2] => Array
(
[month_year] => 08/08/2018
)
[3] => Array
(
[month_year] => 14/08/2018
)
[4] => Array
(
[month_year] => 20/08/2018
)
[5] => Array
(
[month_year] => 27/08/2018
)
)
In above example, after 20/08/2018, next date will be 26/08/2018 but 26/08/2018 is sunday, so we exclude this sunday by 1 day and next date is now 27/08/2018. 在上面的示例中,在20/08/2018之后,下一个日期将是26/08/2018,但是26/08/2018是星期日,因此我们将该星期天排除在1天之前,下一个日期现在是27/08/2018。
If any occurence of date after calculating interval in between saturday and sunday then skip this weekend by 1 or 2days. 如果在计算周六至周日之间的间隔后发生日期,则将本周末跳过1或2天。
$year = date('Y');
$month = date('n');
$weekend_days = array_filter($allDays[$year][$month], function($d) {
return (date('N', strtotime(date("Y-m-$d"))) >= 6);
});
$allDays[$year][$month] = array_diff($allDays[$year][$month], $weekend_days);
print_r($allDays);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.