如何在MongoDb中简单地执行更新/替换许多文档的操作

Question

This is perhaps one of the most common and basic database operations you can perform. However, how you perform this operation in MongoDb, is elusive.

There's a UpdateManyAsync method in the C# driver. But all I can find for it is examples like;

The following operation updates all documents where violations are greater than 4 and $set a flag for review:

try {
   db.restaurant.updateMany(
      { violations: { $gt: 4 } },
      { $set: { "Review" : true } }
   );
} catch (e) {
   print(e);
}

Frankly I don't know how you guys build your applications but our organization will never embed domain logic like how many violations constitutes a review in our database querying logic. Like all the examples I can find for this operation do.

It seems at best that our option is to use some sort of bulk api for this, which seems unnecessary for such a simple operation. Making the bulk api perform a thousand separate replaces seems ineffective to me, but I might be wrong here?

In other storage technologies and more mature API's all the code necessary to perform this operation is (example Entity framework);

db.UpdateRange(stocks);
await db.SaveChangesAsync();

Is this tracked as a feature request for the Mongo project somewhere?

Answer 1

Bulk API can handle it see code below:

            var updates = new List<WriteModel<CosmosDoc>>();
            foreach (var doc in docs)
            {
                updates.Add(new ReplaceOneModel<CosmosDoc>(doc.Id, doc));
            }
            await MongoDb.DocsCollection.BulkWriteAsync(updates, new BulkWriteOptions() { IsOrdered = false });