[英]Deserialize xml file on android studio
I wrote an app that uses an xml file I created, and I need to deserialize it to a list. 我编写了一个使用创建的xml文件的应用程序,需要将其反序列化为列表。 Each item in the list has some properties and an inside list.
列表中的每个项目都有一些属性和一个内部列表。 For example:
<persons> <person> <FirstName>fn1</FirstName> <LastName>ln1</LastName> <Age>30</Age> <FavoriteColors> <ColorItem> <ColorName>red</ColorName> <IsFavorite>True</IsFavorite> </ColorItem> <ColorItem> <ColorName>blue</ColorName> <IsFavorite>False</IsFavorite> </ColorItem> </FavoriteColors> </person> <person> <FirstName>fn2</FirstName> <LastName>ln2</LastName> <Age>20</Age> <FavoriteColors> <ColorItem> <ColorName>white</ColorName> <IsFavorite>False</IsFavorite> </ColorItem> <ColorItem> <ColorName>black</ColorName> <IsFavorite>False</IsFavorite> </ColorItem> <ColorItem> <ColorName>pink</ColorName> <IsFavorite>True</IsFavorite> </ColorItem> </FavoriteColors> </person> </persons>
I know how to do it on c#, but I'm new to java and couldn't find a way to do that. 例如:
<persons> <person> <FirstName>fn1</FirstName> <LastName>ln1</LastName> <Age>30</Age> <FavoriteColors> <ColorItem> <ColorName>red</ColorName> <IsFavorite>True</IsFavorite> </ColorItem> <ColorItem> <ColorName>blue</ColorName> <IsFavorite>False</IsFavorite> </ColorItem> </FavoriteColors> </person> <person> <FirstName>fn2</FirstName> <LastName>ln2</LastName> <Age>20</Age> <FavoriteColors> <ColorItem> <ColorName>white</ColorName> <IsFavorite>False</IsFavorite> </ColorItem> <ColorItem> <ColorName>black</ColorName> <IsFavorite>False</IsFavorite> </ColorItem> <ColorItem> <ColorName>pink</ColorName> <IsFavorite>True</IsFavorite> </ColorItem> </FavoriteColors> </person> </persons>
我知道如何在c#上进行操作,但是我是java的新手,所以找不到解决方法。 What is the best, shorter and easiest way to do that? 最好,更短和最简单的方法是什么? do I need to build classes for it like in c#?
我需要像在c#中那样为其构建类吗? or are there commands to go threw over the xml elements to build my list?
还是有一些命令可以遍历xml元素来建立我的列表? is json would be better over xml?
json比xml更好吗? if so, how do I deserialize json?
如果是这样,我如何反序列化json? Thanks for the helpers!
感谢您的帮手! :)
:)
For those who need the solution, this is how I solved it. 对于那些需要解决方案的人,这就是我解决的方法。 I used dom parser.
我使用了dom解析器。
First, I created a class for the favoriteColors with its properties. 首先,我为最喜欢的颜色及其属性创建了一个类。
public class FavoriteColors
{
private String ColorName;
private boolean IsFavorite;
public FavoriteColors(String _colorName, boolean _isFavorite)
{
this.ColorName = _colorName;
this.IsFavorite = _isFavorite;
}
}
Then, I created a class for the person with its properties. 然后,我为具有该属性的人创建了一个类。
public class Person
{
private String FirstName;
private String LastName;
private String Age;
private List<FavoriteColors> AllColors = new ArrayList<FavoriteColors>();
public Person(String _firstName, String _lastName, String _age, List<FavoriteColors> _allColors)
{
this.FirstName = _firstName;
this.LastName = _lastName;
this.Age = _age;
for (int i = 0; i < _allColors.size(); i++)
{
this.AllColors.add(_allColors.get(i));
}
}
}
The parse code: You need to read your xml file to a string (or in any other way you choose) and the final list where all data is collecting to is listOfPersons, which I defined in the code. 解析代码:您需要将xml文件读取为一个字符串(或以您选择的任何其他方式),并且所有数据收集到的最终列表是listOfPersons,我在代码中定义了该列表。
public static void main(String[] args)
{
String xmlFile = "your xml file" // read your xml file to string
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
try
{
DocumentBuilder builder = factory.newDocumentBuilder();
InputSource is = new InputSource(new StringReader(xmlFile));
Document document = builder.parse(is);
List<Person> listOfPersons = new ArrayList<Person>();
NodeList nodeList = document.getDocumentElement().getChildNodes();
for (int i = 0; i < nodeList.getLength(); i++)
{
Node node = nodeList.item(i);
if (node.getNodeType() == Node.ELEMENT_NODE)
{
Element elem = (Element) node;
String firstNameText = "";
if (elem.getElementsByTagName("FirstName").item(0).getChildNodes().item(0) != null)
{
firstNameText = elem.getElementsByTagName("FirstName").item(0).getChildNodes().item(0).getNodeValue();
}
String lastNameText = "";
if (elem.getElementsByTagName("LastName").item(0).getChildNodes().item(0) != null)
{
lastNameText = elem.getElementsByTagName("LastName").item(0).getChildNodes().item(0).getNodeValue();
}
String ageText = "";
if (elem.getElementsByTagName("Age").item(0).getChildNodes().item(0) != null)
{
ageText = elem.getElementsByTagName("Age").item(0).getChildNodes().item(0).getTextContent();
}
List<FavoriteColors> listOfColors = new ArrayList<FavoriteColors>();
NodeList nl = elem.getElementsByTagName("FavoriteColors").item(0).getChildNodes();
for (int j = 0; j < nl.getLength(); j++)
{
Node n = nl.item(j);
if (n.getNodeType() == Node.ELEMENT_NODE)
{
Element e = (Element) n;
String colorName = "";
if (e.getElementsByTagName("ColorName").item(0).getChildNodes().item(0) != null)
{
colorName = e.getElementsByTagName("ColorName").item(0).getChildNodes().item(0).getNodeValue();
}
boolean isFavorite = false;
if (e.getElementsByTagName("IsFavorite").item(0).getChildNodes().item(0).getNodeValue() != null)
{
isFavorite = Boolean.parseBoolean(e.getElementsByTagName("IsFavorite").item(0).getChildNodes().item(0).getNodeValue());
}
listOfColors.add(new FavoriteColors(colorName, isFavorite));
}
}
listOfPersons.add(new Person(firstNameText, lastNameText, ageText, listOfColors));
}
}
}
catch (ParserConfigurationException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
} catch (SAXException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Hope it will help others. 希望它能帮助别人。 :)
:)
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